d.) What should the speed of sound be in the classroom (19 °C). V19degree = m/s e.) Compare this to the accepted value of 340.29 m/s at sea level. Use a percent error calculation. |theoretical value - experimenmtal value| theoretical value % error = x 100%
d.) What should the speed of sound be in the classroom (19 °C). V19degree = m/s e.) Compare this to the accepted value of 340.29 m/s at sea level. Use a percent error calculation. |theoretical value - experimenmtal value| theoretical value % error = x 100%
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Please answer parts d and e using the info given. All other questions have been answered and highlighted. Show all work and circle your answers for parts d and e.
Thank you

Transcribed Image Text:2.) The speed of sound in air depends on the temperature of the air:
Vsound = 331.4+0.6 * T (measured in C)
a.) Compute the speed of sound at 0 °C.
V= (331.4 + 0.6 x 0 °Cm/s
Vodegree 331.4 m/s
b.) Compute the speed of sound at 1 °C.
V= (331.4 + 0.6 x 1 C) m/s
Videgree 332 m/s
c.) How many meters per second does the speed of sound increase for every one-
degree change in temperature (Celsius)?
0.6 m/s is the speed of sound increases for every 1 C change in temperature
d.) What should the speed of sound be in the classroom (19 °C).
V19degree =
m/s
e.) Compare this to the accepted value of 340.29 m/s at sea level. Use a percent
error calculation.
|theoretical value - experimemtal value|
theoretical value
% error =
x 100%
%% error =
||

Transcribed Image Text:1) A popular way to measure the distance to lightning is to start counting, one count
per second as soon as you see the flash. Stop counting when you hear the thunder
and divide by five to get the distance in miles (this means that 5 seconds
corresponds to a distance of 1 mile). Use this information to estimate the speed of
sound in m/s.
Distance
We know from lecture that: Velocity=
Time
and in the case of the lighting/thunder example that: Distance Time
%3D
Combining these two equations we get a value for the speed of sound:
Time
=1/ miles
Time
0.2 miles/
second
Velocity=
second
Use the conversion of 1 mile 1609 m to find an answer for the speed of sound.
Velocity time/5 /time
Velocity 1/5 miles/second
Velocity 0.2 miles/second
Since I mile1609 m
0.2 mile 1609 x 0.2 meter 321.8 m
A Velocity 0.2 miles/second 321.8 m/s
Velocity of sound is 321.8 m/s
JAN
27,350
17
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