Please check if I completed this question correctly. If I solved it correctly. And the answer is correct Image 1: The question Image 2: My work
Please check if I completed this question correctly. If I solved it correctly. And the answer is correct Image 1: The question Image 2: My work
Related questions
Question
Please check if I completed this question correctly. If I solved it correctly. And the answer is correct
Image 1: The question
Image 2: My work
Transcribed Image Text:Hit
A
wire # 2 -
0₁ = 40°
0₂ = 50°
a) Ti Cos 0₁
T₂ cos ₂ = 0
27 T₁ Cos 6₁ = T₂ Cos 0₂
Ti Costi
(
T2
-> T₂ = COS 6₂
8 kat m
Hence, Ti
8.
<wire #1 -▷ Decoration Diagram
and Ti Sin 0₁ + T₂ Sinf₂ = • mg
Sine
Ti sinfi +
+ Cos ₁
we are going
to use equation later.
Ti Costi Sine₂ =
Cos 0₂
Jir: 62
Cos 02
mg
Hence, T₁ = sin Q₁ + Cos 0₁, tanAz
= mg
8x9.8
Hence Ti = Sin 40° + cos 40⁰ tan 50°
77
SO.39455 N
Cos 40°
X
12 = 50.39455 x COS 450
cos so°
-T₂ = 60.05788 N
AL
162
a)
Now given 0₁ = 40⁰ and £₂ = 50° and m=
Free Body Diagram
314
01
mg
To cos d₂ [Bj
T2
T₂ R
0₂ 0101
= 8kg
Tr
my
b) From A ABC sing₂ = I
yo
Apply Newtons second law
T₂ cos 6₂ = man
Ti Cost1 - Tz costz
Tisins + T₂ SinG - nug = may
Now
l=0.3m
T₁ = Sinfi +
T2 sin 02
Ii Cose 1
DC
= Sin 40°
BC
=) 0-3 = sin 40°
=> DC = 0.19284
1
BC=0.3m
The tension for wire I is
T₁ = 50.39.N and wire #2
its tension is T2 = 60.06 N
b): The decoration is suspended
0.19 meter below the
ceiling
Transcribed Image Text:A 8 kg decoration hangs from the ceiling. It is
suspended by 2 wires. The first wire forms a
40° angle with the ceiling. The second wire forms a
50° angle with the ceiling.
a. Find the tension in the 2 wires (including
magnitude and direction)
b. Assuming the wire that forms the 40° angle with
the ceiling has a length of 0.3 metres, how far
below the ceiling is the decoration suspended?
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 3 steps
