Please show all your work the second page is stretched the format how the answer how to be answered please ☺️ show all your wok . Circle your final answer. Please fallow the format please ? Water enters a boiler at 68 degreesFahrenheit[F]The boiler operates for 5 minutes[min]to heat 25 gallons[gal]of water using 5000 British Thermal Units[BTU]of energy.The specific heat capacity of water4.180kilojoules per kilogram kelvinkJWhat is the final temperature in degreesFahrenheit['F]of the water as it exits the boiler? P Determine the energy (@) vequived to heatacupof coffee in units of joules [J].RQ= m cp ATAT= TA - Ti%3DOM: 0.7 kgCp = 4.18 Te Te = 85°CTi= 40°Cm= 0.7 yal 1000 q =700gAT: Tp- Ti = 8°C - 40°C = 45°CQ = m Cp AT = (700 8X4.1845 2)%3DEQ = 131670 J%3D

Given data The initial temperature of the water entering the boiler is given as Ti=68°F. The time…

Answered: Water enters a boiler at 68 degrees…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

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Please show all your work the second page is stretched the format how the answer how to be answered please ☺️ show all your wok . Circle your final answer. Please fallow the format please ?

Water enters a boiler at 68 degrees
Fahrenheit
[F]
The boiler operates for 5 minutes
[min]
to heat 25 gallons
[gal]
of water using 5000 British Thermal Units
[BTU]
of energy.
The specific heat capacity of water
4.180
kilojoules per kilogram kelvin
kJ
What is the final temperature in degrees
Fahrenheit
['F]
of the water as it exits the boiler?

P Determine the energy (@) vequived to heat
a
cup
of coffee in units of joules [J].
RQ= m cp AT
AT= TA - Ti
%3D
OM: 0.7 kg
Cp = 4.18 Te Te = 85°C
Ti= 40°C
m= 0.7 yal 1000 q =
700g
AT: Tp- Ti = 8°C - 40°C = 45°C
Q = m Cp AT = (700 8X4.1845 2)
%3D
E
Q = 131670 J
%3D

Expert Solution

Step 1

Given data

The initial temperature of the water entering the boiler is given as $T_{i} = 68 ° F$ .
The time boiler operates is given as t = 5 min.
The volume of the water is given as V = 25 gallons.
The power utilized by the water is given as P = 5000 BTU.
The specific heat capacity of water is C = 4.180 kJ/kg.K.

The final temperature in degrees Fahrenheit is calculated as,

$P = \frac{m c ∆ T}{t} P = \frac{m c (T_{f} - T_{i})}{t}$

Here, m is the mass of the water.

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