D. Stoichiometry GIVEN: FIND: APPROACH: 22.35 mL of 0.840 M Pb(NO3)2 soľ'n reacts with 1.34 M NaCl(aq) to form PbCl₂(s) volume (L) of NaCl solution required M = mol solute / L solution, AND stoichiometry: balanced equation, then known (Pb(NO3)2)... -> vol of NaCl solution

D. Stoichiometry GIVEN: FIND: APPROACH: 22.35 mL of 0.840 M Pb(NO3)2 soľ'n reacts with 1.34 M NaCl(aq) to form PbCl₂(s) volume (L) of NaCl solution required M = mol solute / L solution, AND stoichiometry: balanced equation, then known (Pb(NO3)2)... -> vol of NaCl solution

Introductory Chemistry: A Foundation

9th Edition

ISBN:9781337399425

Author:Steven S. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Donald J. DeCoste

Chapter15: Solutions

Section: Chapter Questions

Problem 88QAP

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Question

D. Stoichiometry
GIVEN:
FIND:
APPROACH:
22.35 mL of 0.840 M Pb(NO3)2 soľ'n reacts with 1.34 M NaCl(aq) to form
PbCl₂(s)
volume (L) of NaCl solution required
M = mol solute / L solution, AND stoichiometry: balanced equation, then
known (Pb(NO3)2)... -> vol of NaCl solution

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