D. Stoichiometry GIVEN: FIND: APPROACH: 22.35 mL of 0.840 M Pb(NO3)2 soľ'n reacts with 1.34 M NaCl(aq) to form PbCl₂(s) volume (L) of NaCl solution required M = mol solute / L solution, AND stoichiometry: balanced equation, then known (Pb(NO3)2)... -> vol of NaCl solution

D. Stoichiometry GIVEN: FIND: APPROACH: 22.35 mL of 0.840 M Pb(NO3)2 soľ'n reacts with 1.34 M NaCl(aq) to form PbCl₂(s) volume (L) of NaCl solution required M = mol solute / L solution, AND stoichiometry: balanced equation, then known (Pb(NO3)2)... -> vol of NaCl solution

Chemistry: An Atoms First Approach

2nd Edition

ISBN:9781305079243

Author:Steven S. Zumdahl, Susan A. Zumdahl

Publisher:Steven S. Zumdahl, Susan A. Zumdahl

Chapter10: Properties Of Solutions

Section: Chapter Questions

Problem 31E: Common commercial acids and bases are aqueous solutions with the following properties: Density...

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Question

D. Stoichiometry
GIVEN:
FIND:
APPROACH:
22.35 mL of 0.840 M Pb(NO3)2 soľ'n reacts with 1.34 M NaCl(aq) to form
PbCl₂(s)
volume (L) of NaCl solution required
M = mol solute / L solution, AND stoichiometry: balanced equation, then
known (Pb(NO3)2)... -> vol of NaCl solution

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