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d. 32 drops of 6.0M NaOH added to 40.0 mL of a solution that is 0.65M in acetic acid and 0.25M in calcium acetate. 20 drops = 1 mL

d. 32 drops of 6.0M NaOH added to 40.0 mL of a solution that is 0.65M in acetic acid and 0.25M in calcium acetate. 20 drops = 1 mL

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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1. Calculate the pH of the following solutions: a. A solution prepared by mixing 30.0 mL of 2.0M NaOH with 300.0 mL of 0.55M formic acid. b. A solution prepared by adding 0.030 moles of HNO₃ to 25.0 mL of 2.0M potassium carbonate. c. 10.0 mL of 1.0M HCl added to 50.0 mL of a solution that is 0.40M in both HF and NaF. d. 32 drops of 6.0M NaOH added to 40.0 mL of a solution that is 0.65M in acetic acid and 0.25M in calcium acetate. (20 drops = 1 mL)
Transcribed Image Text:1. Calculate the pH of the following solutions: a. A solution prepared by mixing 30.0 mL of 2.0M NaOH with 300.0 mL of 0.55M formic acid. b. A solution prepared by adding 0.030 moles of HNO₃ to 25.0 mL of 2.0M potassium carbonate. c. 10.0 mL of 1.0M HCl added to 50.0 mL of a solution that is 0.40M in both HF and NaF. d. 32 drops of 6.0M NaOH added to 40.0 mL of a solution that is 0.65M in acetic acid and 0.25M in calcium acetate. (20 drops = 1 mL)
Expert Solution
Step 1

Given,

Concentration of CH3COOH (aq.) = 0.65 (M) [weak acid]

Concentration of CH3COOCa (aq.) = 0.25 (M) [salt]

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