[References] A 2.66-g sample of a pure compound, with formula M2SO̟, was dissolved in water and treated with an excess of aqueous calcium chloride, resulting in the precipitation of all the sulfate ions as calcium sulfate. The precipitate was collected, dried, and found to weigh 1.36 g. Determine the atomic mass of M, and identify M. Atomic mass = u Element M:
[References] A 2.66-g sample of a pure compound, with formula M2SO̟, was dissolved in water and treated with an excess of aqueous calcium chloride, resulting in the precipitation of all the sulfate ions as calcium sulfate. The precipitate was collected, dried, and found to weigh 1.36 g. Determine the atomic mass of M, and identify M. Atomic mass = u Element M:
Chemistry
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Chapter1: Chemical Foundations
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*(X Con (110 M Inb
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[References]
A 2.66-g sample of a pure compound, with formula MSO̟, was dissolved in water and treated with an excess of
aqueous calcium chloride, resulting in the precipitation of all the sulfate ions as calcium sulfate. The precipitate was
collected, dried, and found to weigh 1.36 g. Determine the atomic mass of M, and identify M.
Atomic mass =
Element M:
Try Another Version
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Transcribed Image Text:logi
*(X Con (110 M Inb
Doc (10
D (10
Doc M You
88 Nex Luk0 Mic tOP
m/ilrn/takeAssignment/takeCovalentActivity.do?locator=assignment-take
erosoft Office Ho...
Imported From Fire...
G3 Google Drive GK3
G1-Google Drve New Guiding Cours...
SL What did you do la..
[References]
A 2.66-g sample of a pure compound, with formula MSO̟, was dissolved in water and treated with an excess of
aqueous calcium chloride, resulting in the precipitation of all the sulfate ions as calcium sulfate. The precipitate was
collected, dried, and found to weigh 1.36 g. Determine the atomic mass of M, and identify M.
Atomic mass =
Element M:
Try Another Version
3 item attempts remaining
Submit Answer
Expert Solution

Step 1
Given : Mass of M2SO4 sample = 2.66 g
And mass of calcium sulfate i.e CaSO4 precipitate formed = 1.36 g.
Molar mass of CaSO4 = Atomic mass of Ca + Atomic mass of S + Atomic mass of O X 4 = 40 + 32 + 16 X 4 = 136 g/mol.
Since mass = moles X molar mass
=> 1.36 = moles of CaSO4 formed X 136
=> Moles of CaSO4 formed = 0.01 mol.
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