(d) Interpret the hypotheses H: Bo + 1268, = 80 and H: Bo + 126B, < 80. Assuming the filtration rate is 126 kg-DS/m/h, we would test to see if the average moisture content of the compressed pellets is less than 80%. Carry out a hypothesis test at significance level 0.01. Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to three decimal places.) t = P-value = State the conclusion in the problem context. O Reject Ho: There is significant evidence to prove that the true average moisture content for a filtration rate of 126 kg-DS/m/hr is less than 80%. O Fail to reject Hp: There is significant evidence to prove that the true average moisture content for a filtration rate of 126 kg-DS/m/hr is less than 80%. O Reject Hn. There is not significant evidence to prove that the true average moisture content for a filtration rate of 126 kg-DS/m/hr is less than 80%. O Fail to reject Hn: There is not significant evidence to prove that the true average moisture content for a filtration rate of 126 kg-DS/m/hr is less than 80%. You may need to use the appropriate table in the Appendix of Tables to answer this question.

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(d) Interpret the hypotheses H: Bo + 1268, = 80 and H: Bo + 126B, < 80.
Assuming the filtration rate is 126 kg-DS/m/h, we would test to see if the average moisture content of the compressed pellets is less than
80%.
Carry out a hypothesis test at significance level 0.01.
Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to three decimal places.)
t =
P-value =
State the conclusion in the problem context.
O Reject Ho: There is significant evidence to prove that the true average moisture content for a filtration rate of 126 kg-DS/m/hr is less than 80%.
O Fail to reject Hp: There is significant evidence to prove that the true average moisture content for a filtration rate of 126 kg-DS/m/hr is less than 80%.
O Reject Hn. There is not significant evidence to prove that the true average moisture content for a filtration rate of 126 kg-DS/m/hr is less than 80%.
O Fail to reject Hn: There is not significant evidence to prove that the true average moisture content for a filtration rate of 126 kg-DS/m/hr is less than 80%.
You may need to use the appropriate table in the Appendix of Tables to answer this question.
Transcribed Image Text:(d) Interpret the hypotheses H: Bo + 1268, = 80 and H: Bo + 126B, < 80. Assuming the filtration rate is 126 kg-DS/m/h, we would test to see if the average moisture content of the compressed pellets is less than 80%. Carry out a hypothesis test at significance level 0.01. Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to three decimal places.) t = P-value = State the conclusion in the problem context. O Reject Ho: There is significant evidence to prove that the true average moisture content for a filtration rate of 126 kg-DS/m/hr is less than 80%. O Fail to reject Hp: There is significant evidence to prove that the true average moisture content for a filtration rate of 126 kg-DS/m/hr is less than 80%. O Reject Hn. There is not significant evidence to prove that the true average moisture content for a filtration rate of 126 kg-DS/m/hr is less than 80%. O Fail to reject Hn: There is not significant evidence to prove that the true average moisture content for a filtration rate of 126 kg-DS/m/hr is less than 80%. You may need to use the appropriate table in the Appendix of Tables to answer this question.
Japan's high population density has resulted in a multitude of resource-usage problems. One especially serious difficulty concerns waste removal. The article "Innovative Sludge Handling Through Pelletization Thickening"t reported the development of a new compression machine for processing sewage sludge. An important part of the
investigation involved relating the moisture content of compressed pellets (y, in %) to the machine's filtration rate (x, in kg-DS/m/hr). Consider the following data.
125.4 98.3 201.6 147.2
146.0 124.5 112.3 120.2
161.1
178.8
y
77.9 76.9
81.3
80.0
78.1
78.5
77.4
77.2
79.9
80.4
159.4 145.7 74.9 151.5 144.2
124.8 198.6 132.6 159.6 110.7
79.7
79.2 76.9
78.1
79.6
78.3
81.7
76.8
79.1
78.5
Relevant summary quantities are
x; = 2817.4 y, = 1575.5, x2 = 415,815.84, xy, = 222,698.08, y? = 124,149.53. Also, x = 140.87o, y = 78.78, S = 18,928.7020, s = 757.395, and SSE = 9.222. The estimated standard deviation is o = 0.716 and the equation of the least squares line is y = 73.140 + 0.040x.
Consider the filtration rate-moisture content data introduced above.
Transcribed Image Text:Japan's high population density has resulted in a multitude of resource-usage problems. One especially serious difficulty concerns waste removal. The article "Innovative Sludge Handling Through Pelletization Thickening"t reported the development of a new compression machine for processing sewage sludge. An important part of the investigation involved relating the moisture content of compressed pellets (y, in %) to the machine's filtration rate (x, in kg-DS/m/hr). Consider the following data. 125.4 98.3 201.6 147.2 146.0 124.5 112.3 120.2 161.1 178.8 y 77.9 76.9 81.3 80.0 78.1 78.5 77.4 77.2 79.9 80.4 159.4 145.7 74.9 151.5 144.2 124.8 198.6 132.6 159.6 110.7 79.7 79.2 76.9 78.1 79.6 78.3 81.7 76.8 79.1 78.5 Relevant summary quantities are x; = 2817.4 y, = 1575.5, x2 = 415,815.84, xy, = 222,698.08, y? = 124,149.53. Also, x = 140.87o, y = 78.78, S = 18,928.7020, s = 757.395, and SSE = 9.222. The estimated standard deviation is o = 0.716 and the equation of the least squares line is y = 73.140 + 0.040x. Consider the filtration rate-moisture content data introduced above.
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