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Name: In salamanders, green skin (G) is dominant yellow skin (g), a detachab
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Description: In salamanders, green skin (G) is dominant yellow skin (g), a detachable tail (D) is dominant over a non-detachable tail(d), and black eyes (B) are dominant over red eyes (b).The following cross is performed between two salamanders: GgDdBb x ggDdBbOn

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In salamanders, green skin (G) is dominant yellow skin (g), a detachable tail (D) is dominant over a non-detachable tail (d), and black eyes (B) are dominant over red eyes (b). The following cross is performed between two salamanders: GgDdBb x ggDdBb On your own paper, draw a forked-line diagram for this cross and clearly show the expected phenotypic proportions (fractions) of the offspring. [Ex: 5/31 G_D_B_]

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I need answer in diagram like this

### Genetics and Probability
#### Punnett Squares and Genetic Crosses

**Objective:** Understand genetic crosses and calculate probabilities using Punnett squares.

**Overview:** This section explores how to predict gene combinations using Punnett squares and calculating their probabilities.

#### Genetic Cross Setup

**Parental Generation (P1):**

- **Cross 1:**
Genotype: \( GgDdBb \times GgDdBB \)
- \(GgDdBb\)
- \(GgDdBB\)

- **Cross 2:**
Genotype:
- \(dd\)
- \(Bb\)

#### Punnett Square Analysis

*Punnett Square for G x g Cross:*
```
G g
G GG Gg
g Gg gg
```

##### Probability Calculations:

1. **\( GgDdBB \):**
- \(Gg \times dd\) = \( \frac{1}{2} Gg \times \frac{1}{2} dd \rightarrow \frac{1}{4} Ggdd \)
- \( \frac{1}{2} Bb \rightarrow \frac{1}{2} \left( \frac{1}{2} \times \frac{1}{2} \right) = \frac{1}{4} Bb \)
- Result: \( GgddBb \)

2. **Additional crosses:**
- **\( GgDdBb \times GgDdBB \)**:
- \( Gg \times Gg \rightarrow \frac{1}{2} \text{BB or } GgDdBb \)
- \( \frac{1}{4}Bb\left(\frac{1}{2} \times \frac{1}{2}\right) = \frac{1}{4} GgDdBb \)

3. **\( ggDdBB \) and beyond:**
- Calculate different combinations by multiplying fractions.

Below is an example summary:

\[
\begin{aligned}
&\frac{1}{2} Bb \rightarrow \left( \frac{1}{4} \right) \left( \frac{1}{2} \right) \left( \frac{1}{2} \right) \rightarrow GgDdBb \times \frac{1}{2} GgDdBB \\
&\frac{1

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