d-Base Equilibria and a Strong Base sed to indicate the hydrogen ion plution: H--log[H+] water, in any aqueous solution, the and the hydroxide ion concentration, other by the K of water [OH-]-1.00 x 10-14 value at approximately 297 K. Based on OH are also related to each other as 00=pH + POH Part A 0.20 g of hydrogen chloride (HCI) is dissolved in water to make 4.5 L of solution. What is the pH of the resulting hydrochloric acid solution? Express the pH numerically to two decimal places. ▸ View Available Hint(s) pH = Submit Part B [ΨΕΙ ΑΣΦ ? Review | C 0.35 g of sodium hydroxide (NaOH) pellets are dissolved in water to make 8.0 L of solution. What is the pH of this solution?
Ionic Equilibrium
Chemical equilibrium and ionic equilibrium are two major concepts in chemistry. Ionic equilibrium deals with the equilibrium involved in an ionization process while chemical equilibrium deals with the equilibrium during a chemical change. Ionic equilibrium is established between the ions and unionized species in a system. Understanding the concept of ionic equilibrium is very important to answer the questions related to certain chemical reactions in chemistry.
Arrhenius Acid
Arrhenius acid act as a good electrolyte as it dissociates to its respective ions in the aqueous solutions. Keeping it similar to the general acid properties, Arrhenius acid also neutralizes bases and turns litmus paper into red.
Bronsted Lowry Base In Inorganic Chemistry
Bronsted-Lowry base in inorganic chemistry is any chemical substance that can accept a proton from the other chemical substance it is reacting with.
![**Week 3 Assignment: Acid-Base Equilibria**
**pH of a Strong Acid and a Strong Base**
**Understanding pH:**
- The pH is a logarithmic scale used to indicate the hydrogen ion concentration, \([H^+]\), of a solution:
\[
\text{pH} = -\log[H^+]
\]
- Due to the autoionization of water, in any aqueous solution, the hydrogen ion concentration and the hydroxide ion concentration, \([OH^-]\), are related to each other by the \(K_w\) of water:
\[
K_w = [H^+][OH^-] = 1.00 \times 10^{-14}
\]
where \(1.00 \times 10^{-14}\) is the value at approximately 297 K. Based on this relation, the pH and pOH are also related to each other as:
\[
14.00 = \text{pH} + \text{pOH}
\]
**Exercises:**
**Part A:**
- A sample of 0.20 g of hydrogen chloride (HCl) is dissolved in water to make 4.5 L of solution. The task is to determine the pH of the resulting hydrochloric acid solution. The pH should be expressed numerically to two decimal places.
- Input field for pH calculation is provided with a submit button.
**Part B:**
- A sample of 0.35 g of sodium hydroxide (NaOH) pellets is dissolved in water to make 8.0 L of solution. The task is to determine the pH of this solution. The pH should be expressed numerically to two decimal places.
- Input field for pH calculation is also provided with a submit button.
Charts or diagrams are not present in this image.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd28bb5a8-7114-481e-95e9-134d2c6aa143%2Fe4eb776e-9c96-421d-a832-135119fabdee%2F9b0wmfs_processed.jpeg&w=3840&q=75)
![**Week 3 Assignment: Acid-Base Equilibria**
**Problem 16.48 - Enhanced - with Feedback**
**Part A**
Calculate the pH of a 1.50×10⁻² M HNO₃ solution. Express the pH to three decimal places.
[Interactive box with mathematical and input symbols]
pH = [Input Box]
**Submit** [Submit Button] **Request Answer** [Request Answer Button]
---
**Part B**
Calculate the pH of a solution containing 0.420 g of HClO₃ in 2.10 L of solution. Express the pH to three decimal places.
[Interactive box with mathematical and input symbols]
pH = [Input Box]
**Submit** [Submit Button] **Request Answer** [Request Answer Button]
---
**Part C**
Determine the pH of a solution made by diluting 10.00 mL of 1.20 M HCl to a total volume of 0.430 L.
[No further information provided]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd28bb5a8-7114-481e-95e9-134d2c6aa143%2Fe4eb776e-9c96-421d-a832-135119fabdee%2Fzqgn5dq_processed.jpeg&w=3840&q=75)

Step by step
Solved in 3 steps with 2 images









