D 3. Given: 4DBA = 4DBC DB bisects 4ADC Prove: AABD = Acb A B C Statements Reasons 1. 2. 3. 4. 1. 2. 3. Definition of Bisects 4. 5. 5. T R. 4. Given: TR|| QS TR = QS Prove: ATRU = ASQU U Statements Reasons 1. 2. 3. 4TUR 4SUQ 4. 1. 2. 3. 4. alternate interior angles 5. 5. 5. Given: Cis the midpoint of BE , A D ZA = ZD ZB and ZE are right angles Prove: AABC = ADEC B E Statements Reasons 1. 1.
D 3. Given: 4DBA = 4DBC DB bisects 4ADC Prove: AABD = Acb A B C Statements Reasons 1. 2. 3. 4. 1. 2. 3. Definition of Bisects 4. 5. 5. T R. 4. Given: TR|| QS TR = QS Prove: ATRU = ASQU U Statements Reasons 1. 2. 3. 4TUR 4SUQ 4. 1. 2. 3. 4. alternate interior angles 5. 5. 5. Given: Cis the midpoint of BE , A D ZA = ZD ZB and ZE are right angles Prove: AABC = ADEC B E Statements Reasons 1. 1.
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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Transcribed Image Text:3.
Given: 4DBA = 4DBC
DB bisects 4ADC
Prove: AABD = ACBD
A
B
Statements
Reasons
1.
1.
2.
2.
3.
3. Definition of Bisects
4.
4.
5.
5.
T-
-R
4.
Given: TR || QS
U
TR = QS
Prove: ATRU = ASQU
Statements
Reasons
1.
1.
2.
2.
3. 4TUR E 4SUQ
3.
4.
4. alternate interior angles
5.
5.
Given: Cis the midpoint of BE,
ZA = ZD
ZB and ZE are right angles
5.
Prove: AABC = ADEC
B
E
Statements
Reasons
1.
1.
2.
2.
3.
3.
4.
4.
5.
5.
6.
6.
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