Cyclobutane (C4H8) can decompose according to the following reaction. The concentration of cyclobutane versus time for the reaction is plotted below in three ways, including linear trend lines for each plot. C4H8(g) → 2 C2H4(g) a. Write the rate law for the reaction (including the value and units of the rate constant). Explain how you got your answer. b. Determine the concentration of C4H8 after 120 seconds have passed.
Use 3 significant figures. c. Determine the half-life of the reaction after 120 seconds have passed.
Use 3 significant figures.
Cyclobutane (C4H8) can decompose according to the following reaction. The concentration of cyclobutane versus time for the reaction is plotted below in three ways, including linear trend lines for each plot. C4H8(g) → 2 C2H4(g) a. Write the rate law for the reaction (including the value and units of the rate constant). Explain how you got your answer. b. Determine the concentration of C4H8 after 120 seconds have passed. Use 3 significant figures. c. Determine the half-life of the reaction after 120 seconds have passed. Use 3 significant figures.
Introductory Chemistry: A Foundation
9th Edition
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Donald J. DeCoste
Chapter21: Biochemistry
Section: Chapter Questions
Problem 1QAP
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Cyclobutane (C4H8) can decompose according to the following reaction. The concentration of cyclobutane versus time for the reaction is plotted below in three ways, including linear trend lines for each plot.
C4H8(g) → 2 C2H4(g)
a. Write the rate law for the reaction (including the value and units of the rate constant). Explain how you got your answer.
b. Determine the concentration of C4H8 after 120 seconds have passed. Use 3 significant figures.
c. Determine the half-life of the reaction after 120 seconds have passed. Use 3 significant figures.
![In[C4H8] vs Time
0.000
y = -0.0112x – 0.0002
-0.300
-0.600
-0.900
-1.200
0.0
30.0
60.0
90.0
120.0
Time (s)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F07c73071-4878-4033-a4bc-64226d892a5a%2F0af0dd13-3b53-4467-bb5d-ca53acb4d4c8%2Fsbj8fx_processed.png&w=3840&q=75)
Transcribed Image Text:In[C4H8] vs Time
0.000
y = -0.0112x – 0.0002
-0.300
-0.600
-0.900
-1.200
0.0
30.0
60.0
90.0
120.0
Time (s)
![1/[C4H8] vs Time
4.000
y = 0.0204x + 0.845
3.000
2.000
1.000
0.000
+
0.0
30.0
60.0
90.0
120.0
Time (s)
1/[C4H8] (1/M)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F07c73071-4878-4033-a4bc-64226d892a5a%2F0af0dd13-3b53-4467-bb5d-ca53acb4d4c8%2F9zur8x_processed.png&w=3840&q=75)
Transcribed Image Text:1/[C4H8] vs Time
4.000
y = 0.0204x + 0.845
3.000
2.000
1.000
0.000
+
0.0
30.0
60.0
90.0
120.0
Time (s)
1/[C4H8] (1/M)
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