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a b. C. d. 27. e. The kinetics of the reaction, 4 HBr(g) + O2(g) → 2 H₂O(g) + 2 Br2(g), was studied at a certain temperature with the results shown in the table below. What is the rate law for this reaction under these conditions? EXPERIMENT 1 2 3 W ks 4 Rate = k [HBr]4[0₂] Rate=k [HBr][0₂] Rate=k [HBr]2[0₂] Rate = k [HBr][0₂]² Rate = k [HBr]2[0₂]² [HBr] (M) 0.00382 0.00382 0.00764 0.00764 [0₂] (M) 0.00382 0.00764 0.00382 0.00764 INITIAL RATE (M/s) 0.0984 0.197 0.197 0.393

a b. C. d. 27. e. The kinetics of the reaction, 4 HBr(g) + O2(g) → 2 H₂O(g) + 2 Br2(g), was studied at a certain temperature with the results shown in the table below. What is the rate law for this reaction under these conditions? EXPERIMENT 1 2 3 W ks 4 Rate = k [HBr]4[0₂] Rate=k [HBr][0₂] Rate=k [HBr]2[0₂] Rate = k [HBr][0₂]² Rate = k [HBr]2[0₂]² [HBr] (M) 0.00382 0.00382 0.00764 0.00764 [0₂] (M) 0.00382 0.00764 0.00382 0.00764 INITIAL RATE (M/s) 0.0984 0.197 0.197 0.393

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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a b. C. d. 27. e. The kinetics of the reaction, 4 HBr(g) + O2(g) → 2 H₂O(g) + 2 Br2(g), was studied at a certain temperature with the results shown in the table below. What is the rate law for this reaction under these conditions? EXPERIMENT 1 2 3 Whak 4 Rate = k [HBr]4[0₂] Rate = k [HBr][0₂] Rate = k [HBr]2[0₂] Rate = k [HBr][0₂]² Rate = k [HBr]2[0₂]² [HBr] (M) 0.00382 0.00382 0.00764 0.00764 [0₂] (M) 0.00382 0.00764 0.00382 0.00764 INITIAL RATE (M/s) 0.0984 0.197 0.197 0.393
Transcribed Image Text:a b. C. d. 27. e. The kinetics of the reaction, 4 HBr(g) + O2(g) → 2 H₂O(g) + 2 Br2(g), was studied at a certain temperature with the results shown in the table below. What is the rate law for this reaction under these conditions? EXPERIMENT 1 2 3 Whak 4 Rate = k [HBr]4[0₂] Rate = k [HBr][0₂] Rate = k [HBr]2[0₂] Rate = k [HBr][0₂]² Rate = k [HBr]2[0₂]² [HBr] (M) 0.00382 0.00382 0.00764 0.00764 [0₂] (M) 0.00382 0.00764 0.00382 0.00764 INITIAL RATE (M/s) 0.0984 0.197 0.197 0.393
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