cycle has nön expansion processes. Otto cycle display ratio is 6, isentropic efficiency 85% and isentropic expansion efficiency 90%. At the beginning of the compression process, the air has a pressure of 101.3 kPa and a temperature of 25 ° C. The maximum temperature of the cycle can be taken as 1300 K and possible 4 MPa. (The thermal source temperature is 2000 K and the dead state temperature is 293.15 K). www
cycle has nön expansion processes. Otto cycle display ratio is 6, isentropic efficiency 85% and isentropic expansion efficiency 90%. At the beginning of the compression process, the air has a pressure of 101.3 kPa and a temperature of 25 ° C. The maximum temperature of the cycle can be taken as 1300 K and possible 4 MPa. (The thermal source temperature is 2000 K and the dead state temperature is 293.15 K). www
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![1- An Otto cycle has non-isentropic content and expansion
processes. Otto cycle display ratio is 6, isentropic efficiency
85% and isentropic expansion efficiency 90%. At the
beginning of the compression process, the air has a pressure
of 101.3 kPa and a temperature of 25 ° C. The maximum
temperature of the cycle can be taken as 1300 K and possible
4 MPa. (The thermal source temperature is 2000 K and the
dead state temperature is 293.15 K).
a) Draw the T (K) - s (kJ / kgK) diagram to include isentropic
and non-isentropic curves.
b) Under the room supply constant specific heats approach,
find the heat available [kJ / kg] and the net work output as [kJ
/ kg].
c) Find the heat use as [kJ / kg] and the net work output as
[kJ / kg] under the variable specific heats approximation.
d) Calculating the exergy destruction in [kJ / kg] for the
expansion process under variable specific heats approach.
e) Find the energy and exergy efficiencies in [%] for the room
supply constant specific heats approach cycle.
f) Find the energy and exergy efficiencies for the cycle under
www d
variable specific heats approach as [%].](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd22d8c6c-5213-460e-a55c-08f41f5cc8e8%2Faf5581b0-5a3c-4706-92b2-dd098c71f563%2F63c4gcj_processed.png&w=3840&q=75)
Transcribed Image Text:1- An Otto cycle has non-isentropic content and expansion
processes. Otto cycle display ratio is 6, isentropic efficiency
85% and isentropic expansion efficiency 90%. At the
beginning of the compression process, the air has a pressure
of 101.3 kPa and a temperature of 25 ° C. The maximum
temperature of the cycle can be taken as 1300 K and possible
4 MPa. (The thermal source temperature is 2000 K and the
dead state temperature is 293.15 K).
a) Draw the T (K) - s (kJ / kgK) diagram to include isentropic
and non-isentropic curves.
b) Under the room supply constant specific heats approach,
find the heat available [kJ / kg] and the net work output as [kJ
/ kg].
c) Find the heat use as [kJ / kg] and the net work output as
[kJ / kg] under the variable specific heats approximation.
d) Calculating the exergy destruction in [kJ / kg] for the
expansion process under variable specific heats approach.
e) Find the energy and exergy efficiencies in [%] for the room
supply constant specific heats approach cycle.
f) Find the energy and exergy efficiencies for the cycle under
www d
variable specific heats approach as [%].
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