Curved arrows are used to illustrate the flow of electrons. Follow the curved arrows and draw the products of the following reaction. Include all lone pairs and charges as appropriate. HBr Select to Draw J HBr Select to Draw

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**Educational Website Transcription:**

**Reaction Mechanism and Product Formation Using Curved Arrows**

Curved arrows are used to illustrate the flow of electrons. Follow the curved arrows and draw the products of the following reaction. Include all lone pairs and charges as appropriate.

**Diagram Description:**

The diagram shows a reaction involving an alkene and hydrogen bromide (HBr).

- The alkene structure consists of a carbon chain with a double bond.
- The curved arrows indicate the movement of electrons:
  - One arrow shows the electron pair from the double bond moving to the hydrogen (H) of HBr.
  - Another arrow shows the electron pair from the H-Br bond moving to bromine (Br), indicating its departure as a bromide ion (Br⁻).

**Reaction Description:**

- The reaction begins as the pi electrons from the alkene attack the hydrogen of HBr.
- This results in the formation of a carbocation on the carbon atom that was part of the double bond, and Br⁻ as a departing ion.

Below the reaction mechanism, there are two boxes labeled "Select to Draw" linked with arrows. These boxes are meant for drawing the subsequent products of the reaction, highlighting different pathways and potential rearrangements.

The exercise involves determining the appropriate structural formulas for the product or products formed and indicating all relevant lone pairs and formal charges. Experiment with both regiochemical outcomes to enhance understanding of reaction mechanisms.
Transcribed Image Text:**Educational Website Transcription:** **Reaction Mechanism and Product Formation Using Curved Arrows** Curved arrows are used to illustrate the flow of electrons. Follow the curved arrows and draw the products of the following reaction. Include all lone pairs and charges as appropriate. **Diagram Description:** The diagram shows a reaction involving an alkene and hydrogen bromide (HBr). - The alkene structure consists of a carbon chain with a double bond. - The curved arrows indicate the movement of electrons: - One arrow shows the electron pair from the double bond moving to the hydrogen (H) of HBr. - Another arrow shows the electron pair from the H-Br bond moving to bromine (Br), indicating its departure as a bromide ion (Br⁻). **Reaction Description:** - The reaction begins as the pi electrons from the alkene attack the hydrogen of HBr. - This results in the formation of a carbocation on the carbon atom that was part of the double bond, and Br⁻ as a departing ion. Below the reaction mechanism, there are two boxes labeled "Select to Draw" linked with arrows. These boxes are meant for drawing the subsequent products of the reaction, highlighting different pathways and potential rearrangements. The exercise involves determining the appropriate structural formulas for the product or products formed and indicating all relevant lone pairs and formal charges. Experiment with both regiochemical outcomes to enhance understanding of reaction mechanisms.
**Exercise Instructions: Resonance Structure of Thiophene**

**Task:** 
Draw a resonance structure of thiophene that has the same number of pi bonds as the original structure. Include all lone pairs in your structure.

**Visual Element:**
- The given image depicts a molecular structure of thiophene, a five-membered ring with alternating single and double bonds, including a sulfur atom. The sulfur atom has two lone pairs of electrons represented as dots.

**Guidelines:**
- Analyze the original thiophene structure.
- Ensure that your resonance structure retains the same number of pi bonds (double bonds).
- Clearly indicate the lone pairs, especially on the sulfur atom, in your drawing.
- Create your drawing in the designated area marked by a red dashed box.

**Additional Note:**
Resonance structures are a way to represent the delocalization of electrons within a molecule. The goal is to visualize potential alternative electron configurations while maintaining the same arrangement of atoms.
Transcribed Image Text:**Exercise Instructions: Resonance Structure of Thiophene** **Task:** Draw a resonance structure of thiophene that has the same number of pi bonds as the original structure. Include all lone pairs in your structure. **Visual Element:** - The given image depicts a molecular structure of thiophene, a five-membered ring with alternating single and double bonds, including a sulfur atom. The sulfur atom has two lone pairs of electrons represented as dots. **Guidelines:** - Analyze the original thiophene structure. - Ensure that your resonance structure retains the same number of pi bonds (double bonds). - Clearly indicate the lone pairs, especially on the sulfur atom, in your drawing. - Create your drawing in the designated area marked by a red dashed box. **Additional Note:** Resonance structures are a way to represent the delocalization of electrons within a molecule. The goal is to visualize potential alternative electron configurations while maintaining the same arrangement of atoms.
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