Current Attempt in Progress Your answer is partially correct. A 2.03-g sample of benzoic acid (C,H,O₂) is burned in a constant-volume calorimeter that has a heat capacity of 5.93 kJ/°C. The temperature increases from 24.5 °C to 33.5 °C. a) Determine the amount of heat released (in kJ). 53.37 b) Determine the molar energy of combustion of benzoic acid (in kJ/mol). i 8.9 kJ eTextbook and Media kJ/mol

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**Title: Calorimetry Calculation of Benzoic Acid Combustion**

**Experiment Overview:**
A given sample of benzoic acid (C₇H₆O₂), weighing 2.03 grams, is combusted in a constant-volume calorimeter with a heat capacity of 5.93 kJ/°C. The temperature recorded in the calorimeter increases from 24.5 °C to 33.5 °C.

**Tasks:**

a) **Determining the Amount of Heat Released (in kJ):**
To find the amount of heat (q) released, we use the formula:
\[ q = C \times \Delta T \]
Where:
- \( C \) is the heat capacity of the calorimeter.
- \( \Delta T \) is the change in temperature.

Given:
- \( C = 5.93 \) kJ/°C
- \( \Delta T = (33.5 - 24.5) °C = 9 °C \)

So,
\[ q = 5.93 \times 9 = 53.37 \text{ kJ} \]

b) **Determining the Molar Energy of Combustion of Benzoic Acid (in kJ/mol):**
We need to calculate the molar energy of combustion for benzoic acid. 

- The molar mass of benzoic acid (C₇H₆O₂) is computed using the periodic table:
  \[ (\text{7 Carbon} \times 12.01) + (\text{6 Hydrogen} \times 1.01) + (\text{2 Oxygen} \times 16.00) \]
  \[ = 84.07 + 6.06 + 32.00 \]
  \[ = 122.13 \text{ g/mol} \]

Using the heat released in the earlier calculation:
Given sample weight = 2.03 g

To find the heat released per mole:
\[ \text{Moles of benzoic acid} = \frac{2.03 \text{ g}}{122.13 \text{ g/mol}} \approx 0.0166 \text{ mol} \]

The molar heat of combustion is then:
\[ \text{Molar energy (kJ/mol)} = \frac{q}{\text{moles of benzo
Transcribed Image Text:**Title: Calorimetry Calculation of Benzoic Acid Combustion** **Experiment Overview:** A given sample of benzoic acid (C₇H₆O₂), weighing 2.03 grams, is combusted in a constant-volume calorimeter with a heat capacity of 5.93 kJ/°C. The temperature recorded in the calorimeter increases from 24.5 °C to 33.5 °C. **Tasks:** a) **Determining the Amount of Heat Released (in kJ):** To find the amount of heat (q) released, we use the formula: \[ q = C \times \Delta T \] Where: - \( C \) is the heat capacity of the calorimeter. - \( \Delta T \) is the change in temperature. Given: - \( C = 5.93 \) kJ/°C - \( \Delta T = (33.5 - 24.5) °C = 9 °C \) So, \[ q = 5.93 \times 9 = 53.37 \text{ kJ} \] b) **Determining the Molar Energy of Combustion of Benzoic Acid (in kJ/mol):** We need to calculate the molar energy of combustion for benzoic acid. - The molar mass of benzoic acid (C₇H₆O₂) is computed using the periodic table: \[ (\text{7 Carbon} \times 12.01) + (\text{6 Hydrogen} \times 1.01) + (\text{2 Oxygen} \times 16.00) \] \[ = 84.07 + 6.06 + 32.00 \] \[ = 122.13 \text{ g/mol} \] Using the heat released in the earlier calculation: Given sample weight = 2.03 g To find the heat released per mole: \[ \text{Moles of benzoic acid} = \frac{2.03 \text{ g}}{122.13 \text{ g/mol}} \approx 0.0166 \text{ mol} \] The molar heat of combustion is then: \[ \text{Molar energy (kJ/mol)} = \frac{q}{\text{moles of benzo
**Current Attempt in Progress**

**❌ Incorrect.**

Determine the standard enthalpy change for the following reaction:

\[ 2 \text{NO(g)} + \text{O}_2(\text{g}) \rightarrow 2 \text{NO}_2(\text{g}) \]

\[ \Delta H = 114.14 \text{ kJ} \]

**eTextbook and Media**

[Save for Later]  

### Explanation:

The image shows a question from a chemistry problem set asking students to determine the standard enthalpy change for a chemical reaction. The reaction is given as:

\[ 2 \text{NO(g)} + \text{O}_2(\text{g}) \rightarrow 2 \text{NO}_2(\text{g}) \]

The user input the value "114.14 kJ" as the enthalpy change, but the system marked this answer as incorrect.

**Note**: This transcription and analysis are provided for educational purposes to help students understand the type of feedback they might receive when solving enthalpy problems.
Transcribed Image Text:**Current Attempt in Progress** **❌ Incorrect.** Determine the standard enthalpy change for the following reaction: \[ 2 \text{NO(g)} + \text{O}_2(\text{g}) \rightarrow 2 \text{NO}_2(\text{g}) \] \[ \Delta H = 114.14 \text{ kJ} \] **eTextbook and Media** [Save for Later] ### Explanation: The image shows a question from a chemistry problem set asking students to determine the standard enthalpy change for a chemical reaction. The reaction is given as: \[ 2 \text{NO(g)} + \text{O}_2(\text{g}) \rightarrow 2 \text{NO}_2(\text{g}) \] The user input the value "114.14 kJ" as the enthalpy change, but the system marked this answer as incorrect. **Note**: This transcription and analysis are provided for educational purposes to help students understand the type of feedback they might receive when solving enthalpy problems.
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