Cu2+ + Fe Cu + Fe²+ The reaction is assumed to be that (Cu2+) =(Fe2+) =1.0M and T = 298 K. As the reaction proceeds, Cu²+ =0.50 M while Fe2+ =1.50M. This occur after one minute. What is the EMF of the cell? What is the E of the cell after one minute? What is the Keq for this reaction? (Express in scientific notation, in this manner, ex. 1.25 x 10^+3 All answers in 2 decimal places.
Cu2+ + Fe Cu + Fe²+ The reaction is assumed to be that (Cu2+) =(Fe2+) =1.0M and T = 298 K. As the reaction proceeds, Cu²+ =0.50 M while Fe2+ =1.50M. This occur after one minute. What is the EMF of the cell? What is the E of the cell after one minute? What is the Keq for this reaction? (Express in scientific notation, in this manner, ex. 1.25 x 10^+3 All answers in 2 decimal places.
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter17: Electrochemistry
Section: Chapter Questions
Problem 105QAP: Consider a voltaic cell in which the following reaction occurs. Zn(s)+Sn2+(aq)Zn2+(aq)+Sn(s) (a)...
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![Question 15
Given the reaction:
Cu2+ + Fe Cu + Fe2+
The reaction is assumed to be that (Cu²+) =(Fe2+) = 1.0M and T = 298 K. As the reaction proceeds, Cu²+ =0.50 M while Fe2+ =1.50M. This occur after one minute.
What is the EMF of the cell?
What is the E of the cell after one minute?
What is the Keq for this reaction?
(Express in scientific notation, in this manner, ex. 1.25 x 10^+3
All answers in 2 decimal places.
Weak Oxidizing Agents/Strong Reducing Agents
Standard Reduction Potential Table (at 25°C, 101kPa, 1M)
Half-Reaction
Lit+e → Li
Al+3+3e → Al
volts
-3.04
-1.68
-0.76
Zn+2 +2e → Zn
Fe +2 +2e → Fe
-0.44
2H₂O +2e → H₂ + 2OH-
-0.41
Ni+2 +2e → Ni
-0.26
Pb+2 +2e → Pb
-0.13
0.00
2H+ + 2e →→ H₂
Cu+² +2e → Cu
0.34
0.52
Cu* + e → Cu
Fe+3+eFe +2
0.77
Ag* + e → Ag
0.80
O₂ + 4H2+4e2H₂O
0.82
Br₂ +2e →→2Br
1.07
Cl₂ +2e →→2C1-
1.36
Au +3+3e → Au
1.52
Strong Oxidizing Agents/Weak Reducing Agents](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F95b8c7f4-9d27-4dbc-b0a1-1a63756d6ed9%2F59c33bcd-44db-4f0b-835a-0bdf64fa9761%2F32wbadg_processed.png&w=3840&q=75)
Transcribed Image Text:Question 15
Given the reaction:
Cu2+ + Fe Cu + Fe2+
The reaction is assumed to be that (Cu²+) =(Fe2+) = 1.0M and T = 298 K. As the reaction proceeds, Cu²+ =0.50 M while Fe2+ =1.50M. This occur after one minute.
What is the EMF of the cell?
What is the E of the cell after one minute?
What is the Keq for this reaction?
(Express in scientific notation, in this manner, ex. 1.25 x 10^+3
All answers in 2 decimal places.
Weak Oxidizing Agents/Strong Reducing Agents
Standard Reduction Potential Table (at 25°C, 101kPa, 1M)
Half-Reaction
Lit+e → Li
Al+3+3e → Al
volts
-3.04
-1.68
-0.76
Zn+2 +2e → Zn
Fe +2 +2e → Fe
-0.44
2H₂O +2e → H₂ + 2OH-
-0.41
Ni+2 +2e → Ni
-0.26
Pb+2 +2e → Pb
-0.13
0.00
2H+ + 2e →→ H₂
Cu+² +2e → Cu
0.34
0.52
Cu* + e → Cu
Fe+3+eFe +2
0.77
Ag* + e → Ag
0.80
O₂ + 4H2+4e2H₂O
0.82
Br₂ +2e →→2Br
1.07
Cl₂ +2e →→2C1-
1.36
Au +3+3e → Au
1.52
Strong Oxidizing Agents/Weak Reducing Agents
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