(C#)The following statement declares a StreamReader object variable called "inputFile". Which statement opens a file named "data.txt" to the StreamReader object? StreamReader inputFile;   Question 10 options:   inputFile = open("data.txt");   inputFile = OpenFile("data.txt");   inputFile = File.OpenFile("Data.txt");   inputFile = File.OpenText("Data.txt

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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(C#)The following statement declares a StreamReader object variable called "inputFile". Which statement opens a file named "data.txt" to the StreamReader object?

StreamReader inputFile;
 

Question 10 options:

 
inputFile = open("data.txt");
 
inputFile = OpenFile("data.txt");
 
inputFile = File.OpenFile("Data.txt");
 
inputFile = File.OpenText("Data.txt");
Expert Solution
Step 1

inputFile = File.OpenText("Data.txt");

You can use File.OpenText because it is a static method in the File class that opens a text file, reads its contents and returns a StreamReader object. The StreamReader class provides methods for reading text from a file, such as ReadLine and ReadToEnd, so it is convenient to use File.OpenText to open the file for reading and obtain a StreamReader object in a single line of code.

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