C(s) | K2SO4(aq) | Au(s) the following (Note: For this question it is ok to write "AI203" for Al203 and "02-" for 0²) xidizing Agent K+ with an electrode potential of -2.93 educing Agent 2H20 x with an electrode potential of 1.23 est Oxidizing Agent| K+ with an electrode potential of -2.93 est Reducing Agent 2H20 with an electrode potential of 1.23 x V ore the net cell potential is ( -2.93 x V) - ( 1.23 O V) = -4.16 che table of OAs/RAs that you should have come up with: 0,(g) + 4H*(aq) + 4 e = 2H,0(0) so, (aq) + 4H (aq) + 2c = H,SO,(aq) + H,O(1) 2H,00 + 2e = H,(g) + 20H (aq) . K'(aq) + e= K(s) +1.23 +0.17 -0.83 -2.93 SRA

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Using the following cell,
C(s) | K2SO4(aq) | Au(s)
identify the following (Note: For this question it is ok to write "AI2O3" for Al2O3 and "02-" for 02-)
Oxidizing Agent
K+
with an electrode potential of -2.93
Reducing Agent
2H20
x with an electrode potential of 1.23
V
K+
Strongest Oxidizing Agent
with an electrode potential of
-2.93
x V
Strongest Reducing Agent 2H2O
with an electrode potential of 1.23
X V
Therefore the net cell potential is ( -2.93
x V) - ( 1.23
9 V) =
-4.16
x V
This is the table of OAs/RAS that you should have come up with:
SOA
Olg) + 4H*(aq) + 4e 2 H,O()
so? (aq)+4 H"(aq)
+1.23
2e = H,SO,(aq) + H,O(1)
+0.17
2H,O()+ 2e2 H(g) + 20H (aq)
-0.83
K'(aq)+ e = K(s)
-2.93
SRA
Note that the So,2-(aq) is only considered when in the presence of an acid (with a H*(aq) ion)
Transcribed Image Text:Using the following cell, C(s) | K2SO4(aq) | Au(s) identify the following (Note: For this question it is ok to write "AI2O3" for Al2O3 and "02-" for 02-) Oxidizing Agent K+ with an electrode potential of -2.93 Reducing Agent 2H20 x with an electrode potential of 1.23 V K+ Strongest Oxidizing Agent with an electrode potential of -2.93 x V Strongest Reducing Agent 2H2O with an electrode potential of 1.23 X V Therefore the net cell potential is ( -2.93 x V) - ( 1.23 9 V) = -4.16 x V This is the table of OAs/RAS that you should have come up with: SOA Olg) + 4H*(aq) + 4e 2 H,O() so? (aq)+4 H"(aq) +1.23 2e = H,SO,(aq) + H,O(1) +0.17 2H,O()+ 2e2 H(g) + 20H (aq) -0.83 K'(aq)+ e = K(s) -2.93 SRA Note that the So,2-(aq) is only considered when in the presence of an acid (with a H*(aq) ion)
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