Create a  ( operator overlod = ) for a doubly linked list, in C++.   for this class  #include using namespace std; class Node{     public:         int data;         Node *next, *prev;                  Node(int val){             data = val;             next = NULL;             prev = NULL;         } }; class DLL{     private:         Node *root;              public:         //default constructor         DLL(){             root = NULL;         }                  //copy constructor         DLL(const DLL& list){             Node *newNode, *tail;             Node *current = list.root;                          while(current != NULL){                 newNode = new Node(current->data);                 if(root == NULL) {                     root = newNode;                     tail = root;                 }                 else{                     tail->next = newNode;                     newNode->prev = tail;                     tail = newNode;                 }                 current = current->next;             }         }         };

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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Question

Create a  ( operator overlod = ) for a doubly linked list, in C++.

 

for this class 

#include<iostream>
using namespace std;

class Node{
    public:
        int data;
        Node *next, *prev;
        
        Node(int val){
            data = val;
            next = NULL;
            prev = NULL;
        }
};

class DLL{
    private:
        Node *root;
        
    public:
        //default constructor
        DLL(){
            root = NULL;
        }
        
        //copy constructor
        DLL(const DLL& list){
            Node *newNode, *tail;
            Node *current = list.root;
            
            while(current != NULL){
                newNode = new Node(current->data);
                if(root == NULL) {
                    root = newNode;
                    tail = root;
                }
                else{
                    tail->next = newNode;
                    newNode->prev = tail;
                    tail = newNode;
                }
                current = current->next;
            }
        }
        };

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