0.418 J K¯'g¬1288298308318Temperature (K)Part AUsing the protein DSC data, calculate the enthalpy change between T = 288 K and T = 318 K. Give your answer in units of kJ per mole. Assume the molar mass of the protein is13000. grams per mole. Hint: You can perform the integration of the heat capacity by estimating the area under the DSC curve and above the baseline. This can be done by dividing thearea into small rectangles and summing the areas of the rectangles.Express your answer to two significant figures and include the appropriate units.

The aim of this question is to explain the heat transfer between 288 K and 318 K based on the DSC…

Answered: Cp(7) 288 0.418 J K ¹g¹ 298 308…

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Cp(7) 288 0.418 J K ¹g¹ 298 308 Temperature (K) 318

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ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

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Question

0.418 J K¯'g¬1
288
298
308
318
Temperature (K)
Part A
Using the protein DSC data, calculate the enthalpy change between T = 288 K and T = 318 K. Give your answer in units of kJ per mole. Assume the molar mass of the protein is
13000. grams per mole. Hint: You can perform the integration of the heat capacity by estimating the area under the DSC curve and above the baseline. This can be done by dividing the
area into small rectangles and summing the areas of the rectangles.
Express your answer to two significant figures and include the appropriate units.

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