Cost of Pizzas A pizza shop owner wishes to find the 90% confidence interval of the true mean cost of a large plain pizza. How large should the sample be if.she wishes to be accurate to within $0.14? A previous study showed that the standard deviation of the price was $0.19. Round your final answer up to the next00whole number.aloThe owner needs at least a sample ofpizzas.

Answered: Image /qna-images/answer/202ab9d0-85a8-47d6-8739-c7e044dc8097.jpg

Answered: Cost of Pizzas A pizza shop owner…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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What is the normal hypothesis and alternative hypothesis?
A variable of a population has a normal distribution. Suppose that you want to find a confidence interval for the population mean. a. If you know the population standard deviation, which procedure would you use?b. If you do not know the population standard deviation, which procedure would you use?
Tina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.
Subject :- Accounting
You work for a soft-drink company in the quality control division. You are interested in the standard deviation of one of your production lines as a measure of consistency. The product is intended to have a mean of 12 ounces, and your team would like the standard deviation to be as low as possible. You gather a random sample of 14 containers. Estimate the population standard deviation at a 90% level of confidence. 12.07 11.96 11.93 12.16 12.06 11.9 12.06 12.21 11.86 12.03 11.86 11.83 11.99 12.09 (Data checksum: 168.01) Note: Keep as many decimals as possible while making these calculations. If possible, keep all answers exact by storing answers as variables on your calculator or computer. a) Find the sample standard deviation: b) Find the lower and upper χ2χ2 critical values at 90% confidence:Lower: Upper: c) Report your confidence interval for σσ: ( , )
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For data of discussion 1 refer to this picture What is the best point estimate for your survey question that you used in Discussion 1? Be sure to include both the correct notation (symbol) and the value. Construct a confidence interval for the responses to your survey. Assume that you do not know the population standard deviation. Indicate your level of confidence and the corresponding critical value. What is the margin of error? If we would increase the sample size to 500 students, what would happen to your margin of error?
You work for a soft-drink company in the quality control division. You are interested in the standard deviation of one of your production lines as a measure of consistency. The product is intended to have a mean of 12 ounces, and your team would like the standard deviation to be as low as possible. You gather a random sample of 15 containers. Estimate the population standard deviation at a 80% level of confidence. 11.86 12.12 12.2 12.08 12.06 12.09 11.92 12.26 12.04 12.1 11.85 11.97 11.85 12 12.01 (Data checksum: 180.41) Keep as many decimals as possible while making these calculations. a) Find the sample standard deviation: b) Find the lower and upper χ2χ2 critical values at 80% confidence:Lower: Upper: c) Report your confidence interval for σσ:
Ages of students: A simple random sample of 70 U.S. college students had a mean age of 21.53 years. Assume the population standard deviation is o - 3.82 years. Construct an 80% confidence interval for the mean age of U.S. college students. Round the answers to two decimal places. An 80% confidence interval for the mean age of U.S. college students is
Researchers studied the mean egg length (in millimeters) for a bird population. After taking a random sample of eggs, they obtained a 95% confidence interval of (45,60). What is the value of the margin of error? Choose the correct answer below. A. 15 mm B. 52.5 mm O c. 7.5 mm O D. 1.96
You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals a random sample of 49 business days, the mean closing price of a certain stock was $114.41 Assume the population standard deviation is $11.35
You work for a soft-drink company in the quality control division. You are interested in the standard deviation of one of your production lines as a measure of consistency. The product is intended to have a mean of 12 ounces, and your team would like the standard deviation to be as low as possible. You gather a random sample of 18 containers. Estimate the population standard deviation at a 80% level of confidence. 12.08 12 12.1 11.98 12.1 12.09 11.91 12.01 11.95 12.12 12 12.1 11.97 11.95 12.07 12.1 11.96 12.02 Note: Keep as many decimals as possible while making these calculations. If possible, keep all answers exact by storing answers as variables on your calculator or computer. a) Find the sample standard deviation: b) Find the lower and upper χ2 critical values at 80% confidence:Lower: Upper: c) Report your confidence interval for σ: ( , )

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