Cost of Pizzas A pizza shop owner wishes to find the 90% confidence interval of the true mean cost of a large plain pizza. How large should the sample be if.she wishes to be accurate to within $0.14? A previous study showed that the standard deviation of the price was $0.19. Round your final answer up to the next00whole number.aloThe owner needs at least a sample ofpizzas.

Answered: Image /qna-images/answer/202ab9d0-85a8-47d6-8739-c7e044dc8097.jpg

Answered: Cost of Pizzas A pizza shop owner…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Suppose you calculate a z-score of -2.2 and the distribution is normal. Then which of the following is a correct interpretation? Group of answer choices None of the above are justified interpretations The observation is about 2.2 standard deviations less than the mean. This means it is less than all but roughly 2.5% of the observations. The observation is about 2.2 times the variance less than the mean. This means it is less than all but roughly 5% of the observations The observation is about 2.2 times the variance less than the mean. This means it is less than all but roughly 2.5% of the observations. The observation is about 2.2 standard deviations less than the mean. This means it is less than all but roughly 5% of the observations.
Subject :- Accounting
Cost of an Operation A medical researcher surveyed 11 hospitals and found that the standard deviation for the cost for removing a person's gall bladder was $57. Assume the variable is normally distributed. Based on this, find the 90% confidence intervals of the population variance and standard deviation. Round the answers to two decimal places.
HW ELEVEN
i need help with the last questions
Cost of Pizzas A pizza shop owner wishes to find the 90% confidence interval of the true mean cost of a large plain pizza. How large should the sample be if she wishes to be accurate to within $0.17 ? A previous study showed that the standard deviation of the price was $0.45 . Round your final answer up to the next whole number. The owner needs at least a sample of pizzas. ?
Cost of Pizzas A pizza shop owner wishes to find the 90% confidence interval of the true mean cost of a large plain pizza. How large should the sample be if she wishes to be accurate to within $0.14? A previous study showed that the standard deviation of the price was $0.34. Round your final answer up to the next whole number. The owner needs at least a sample of pizzas. X
Cost of Pizzas A pizza shop owner wishes to find the 99% confidence interval of the true mean cost of a large plain pizza. How large should the sample be if she wishes to be accurate to within $0.14? A previous study showed that the standard deviation of the price was $0.18. Round your final answer up to the next whole number. The owner needs at least a sample of pizzas.
You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals a random sample of 49 business days, the mean closing price of a certain stock was $114.41 Assume the population standard deviation is $11.35
Hospital Noise Levels Noise levels at various area urban hospitals were measured in decibels. The mean noise level in 169 ward areas was 60.3 decibels, and the population standard deviation is 6.1 . Find the 96% confidence interval of the true mean. Use a graphing calculator and round the answers to one decimal place.
You work for a soft-drink company in the quality control division. You are interested in the standard deviation of one of your production lines as a measure of consistency. The product is intended to have a mean of 12 ounces, and your team would like the standard deviation to be as low as possible. You gather a random sample of 18 containers. Estimate the population standard deviation at a 80% level of confidence. 12.08 12 12.1 11.98 12.1 12.09 11.91 12.01 11.95 12.12 12 12.1 11.97 11.95 12.07 12.1 11.96 12.02 Note: Keep as many decimals as possible while making these calculations. If possible, keep all answers exact by storing answers as variables on your calculator or computer. a) Find the sample standard deviation: b) Find the lower and upper χ2 critical values at 80% confidence:Lower: Upper: c) Report your confidence interval for σ: ( , )

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