(c) If the confidence levels were 98% rather than 80%, would the margin of error be larger or smaller than the result in part (a)? Explain. The margin of error would be (Choose one) since (Choose one) In the confidence level will (Choose one) v thlarger smaller

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How many computers? In a simple random sample of 175 households, the sample mean number of personal computers was 2.94. Assume the population standard deviation is o =0.45. Answer the multiple choice question.
(c) If the confidence levels were 98% rather than 80%, would the margin of error be larger or smaller than the result in
part (a)? Explain.
The margin of error would be (Choose one) v
since (Choose one) - In the confidence
level will (Choose one) ▼
thlarger
smaller
(c) If the confidence levels were 98% rather than 80%, would the margin of error be larger or smaller than the result in
part (a)? Explaln.
The margin of error would be (Choose one) ▼
level will (Choose one) ▼
since (Choose one) - In the confidence
the critical value zp:
an increase
a decrease
(c) If the confidence levels were 98% rather than 80%, would the margin of error be larger or smaller than the result in
part (a)? Explain.
The margin
error would be (Choose one) ▼
since (Choose one) v in the confidence
level will (Choose one) v the critical value zn.
increase
decrease
Transcribed Image Text:(c) If the confidence levels were 98% rather than 80%, would the margin of error be larger or smaller than the result in part (a)? Explain. The margin of error would be (Choose one) v since (Choose one) - In the confidence level will (Choose one) ▼ thlarger smaller (c) If the confidence levels were 98% rather than 80%, would the margin of error be larger or smaller than the result in part (a)? Explaln. The margin of error would be (Choose one) ▼ level will (Choose one) ▼ since (Choose one) - In the confidence the critical value zp: an increase a decrease (c) If the confidence levels were 98% rather than 80%, would the margin of error be larger or smaller than the result in part (a)? Explain. The margin error would be (Choose one) ▼ since (Choose one) v in the confidence level will (Choose one) v the critical value zn. increase decrease
How many computers? In a simple random sample of 175 households, the sample mean number of personal computers was
2.94. Assume the population standard deviation is o =0.45.
Part 1 of 4
Transcribed Image Text:How many computers? In a simple random sample of 175 households, the sample mean number of personal computers was 2.94. Assume the population standard deviation is o =0.45. Part 1 of 4
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