Assume that you want to construct a 95% confidence interval estimate of a population mean. Find an estimate of the sample size needed to obtain the specified margin of error for the 95% confidence interval. The sample standard deviation is given. Margin of error, E = 8.3 grams; sample standard deviation, s = 62.1 grams The required sample size is (Round up to the nearest whole number.)

MATLAB: An Introduction with Applications
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**Calculating Sample Size for a 95% Confidence Interval**

To accurately estimate a population mean with a 95% confidence interval, it is critical to determine the required sample size that allows for the specified margin of error.

**Given:**
- Margin of error, \( E = 8.3 \) grams
- Sample standard deviation, \( s = 62.1 \) grams

**Objective:**
Find the sample size needed to achieve this specified margin of error.

**Solution:**
The sample size formula for a confidence interval of the mean is:

\[ n = \left( \frac{Z \cdot s}{E} \right)^2 \]

Where:
- \( n \) is the desired sample size.
- \( Z \) is the Z-score corresponding to the 95% confidence level. For a 95% confidence level, \( Z \approx 1.96 \).
- \( s \) is the sample standard deviation.
- \( E \) is the margin of error.

**Calculation:**
Substitute the given values into the formula to find \( n \). After computing, remember to round up to the nearest whole number.

**Output:**
The required sample size is a rounded-up value based on the above calculation.

**Instruction:**
Make sure you perform this computation using appropriate tools or mathematical calculations to achieve the accurate sample size for precise data analysis in empirical research.
Transcribed Image Text:**Calculating Sample Size for a 95% Confidence Interval** To accurately estimate a population mean with a 95% confidence interval, it is critical to determine the required sample size that allows for the specified margin of error. **Given:** - Margin of error, \( E = 8.3 \) grams - Sample standard deviation, \( s = 62.1 \) grams **Objective:** Find the sample size needed to achieve this specified margin of error. **Solution:** The sample size formula for a confidence interval of the mean is: \[ n = \left( \frac{Z \cdot s}{E} \right)^2 \] Where: - \( n \) is the desired sample size. - \( Z \) is the Z-score corresponding to the 95% confidence level. For a 95% confidence level, \( Z \approx 1.96 \). - \( s \) is the sample standard deviation. - \( E \) is the margin of error. **Calculation:** Substitute the given values into the formula to find \( n \). After computing, remember to round up to the nearest whole number. **Output:** The required sample size is a rounded-up value based on the above calculation. **Instruction:** Make sure you perform this computation using appropriate tools or mathematical calculations to achieve the accurate sample size for precise data analysis in empirical research.
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The margin of error is 8.3 and the standard deviation is 62.1.

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