Cost of ElectricityA refrigerator is an appliance that is left running all the time.In New Orleans, Louisiana, the average residential electricity rate chargedby Entergy is 9.82¢/kWh. Using this rate, how much will it cost to operate arefrigerator that requires 220 Watts in one month.You can use the following steps:1. Convert power to kW =2. Time (in hours) in one month (30 days) =%3D3. Energy consumption (Power x Time) =4. Cost (Rate x Energy) in dollars =

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Cost of Electricity A refrigerator is an appliance that is left running all the time. In New Orleans, Louisiana, the average residential electricity rate charge by Entergy is 9.82¢/kWh. Using this rate, how much will it cost to operate refrigerator that requires 220 Watts in one month. You can use the following steps: 1. Convert power to kW = 2. Time (in hours) in one month (30 days) = 3. Energy consumption (Power x Time) = %3D 4. Cost (Rate x Energy) in dollars =

Cost of Electricity A refrigerator is an appliance that is left running all the time. In New Orleans, Louisiana, the average residential electricity rate charge by Entergy is 9.82¢/kWh. Using this rate, how much will it cost to operate refrigerator that requires 220 Watts in one month. You can use the following steps: 1. Convert power to kW = 2. Time (in hours) in one month (30 days) = 3. Energy consumption (Power x Time) = %3D 4. Cost (Rate x Energy) in dollars =

An Introduction to Physical Science

14th Edition

ISBN:9781305079137

Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres

Publisher:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres

Chapter4: Work And Energy

Section4.4: Power

Problem 2PQ: Electric bills from power companies charge for so many kilowatt-hours (kWh). What are we paying for?

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Question

Cost of Electricity
A refrigerator is an appliance that is left running all the time.
In New Orleans, Louisiana, the average residential electricity rate charged
by Entergy is 9.82¢/kWh. Using this rate, how much will it cost to operate a
refrigerator that requires 220 Watts in one month.
You can use the following steps:
1. Convert power to kW =
2. Time (in hours) in one month (30 days) =
%3D
3. Energy consumption (Power x Time) =
4. Cost (Rate x Energy) in dollars =

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