Cost of Braces The average cost for teeth straightening with metal braces is approximately $5350. A nationwide franchise think that its cost is below that figure. A random sample of 27 patients across the country had an average cost of $5153 with a standard deviation of S631. At a-0.10, can it be concluded that the mean is less than $53507 Assume that the population is approximately normally distributed. Part: 0 /5 Part 1 of 5 (a) State the hypotheses and identify the claim. Ho: 4 (Choose one) ▼ (Choose one) H: (Choose one) (Choose one) This hypothesis test is a (Choose one) test.

Cost of Braces The average cost for teeth straightening with metal braces is approximately $5350. A nationwide franchise think that its cost is below that figure. A random sample of 27 patients across the country had an average cost of $5153 with a standard deviation of S631. At a-0.10, can it be concluded that the mean is less than $53507 Assume that the population is approximately normally distributed. Part: 0 /5 Part 1 of 5 (a) State the hypotheses and identify the claim. Ho: 4 (Choose one) ▼ (Choose one) H: (Choose one) (Choose one) This hypothesis test is a (Choose one) test.

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Description: Cost of Braces The average cost for teeth straightening with metal braces is approximately $5350. A nationwide franchise thinksthat its cost is below that figure. A random sample of 27 patients across the country had an average cost of $5153 with as

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Measuring lung function: One of the measurements used to determine the health of a person's lungs is the amount of air a person can exhale under force in one second. This is called forced expiratory volume in one second, and is abbreviated FEV₁. Assume the mean FEV₁ for 10-year-old boys is 2.1 liters and that the population standard deviation is 6=0.5. A random sample of 58 10-year- old boys who live in a community with high levels of ozone pollution are found to have a sample mean FEV₁ of 1.98 liters. Can you conclude that the mean FEV₁ in the high-pollution community differs from 2.1 liters? Use the α=0.10 level of significance and the P-value method with the TI-84 calculator. Part 1 of 4 State the appropriate null and alternate hypotheses. Ho: μ = 2.1 H₁:μ #2.1 This hypothesis test is a two-tailed Part: 1 / 4 Part 2 of 4 test. Find the P-value. Round the answer to at least four decimal places. P-value:
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Chapter Exerclse 6-84 (Algo) The Rejuvo Corp. manufactures granite countertop cleaner and polish. Quarterly sales Qis a random variable with a mean of 24,320 bottles and a standard deviation of 3,130 bottles. Variable cost is $13 per unit, and fixed cost is $220,270. (a) Find the mean and standard deviation of Rejuvo's total cost. Mean Standard deviation (b-1) If all bottles are sold, what would the selling price have to be to break even, on average? (Round your answer to 2 declmal places.) Selling price (b-2) If all bottles are sold, what would the selling price have to be to make a profit of $25,695? (Round your answer to 2 declmel places.) Selling price < Prev 2
The mean is 146 and the standard deviation is 35. A score of 41 is how many z-scores below the mean?
Assume the samples are random and independent, the populations are nomally distributed, and the population variances are equal. The table available below shows the prices (in dollars) for a sample of automobile batteries. The prices are classified according to battery type. At a = 0.10, is there enough evidence conclude that at least one mean battery price is different from the others? Complete parts (a) through (e) below. E Click the icon to view the battery cost data. (a) Let u1. P2. H3 represent the mean prices for the group size 35, 65, and 24/24F respectively. Identify the claim and state Ho and H. H Cost of batteries by type The claim is the V hypothesis. Group size 35 Group size 65 Group size 24/24F 101 111 121 124 D 146 173 182 278 124 140 141 89 (b) Find the critical value, Fo, and identify the rejection region. 90 79 84 The rejection region is F Fo, where Fo = (Round to two decimal places as needed.) (c) Find the test statistic F. Print Done F= (Round to two decimal places as…
Chapter 5, Section 2, Exercise 043 Hearing Loss in TeenagersA recent study1 found that, of the 1771 participants aged 12 to 19 in the National Health and Nutrition Examination Survey, 19.5% had some hearing loss (defined as a loss of 15 decibels in at least one ear). This is a dramatic increase from a decade ago. The sample size is large enough to use the normal distribution, and a bootstrap distribution shows that the standard error for the proportion is SE=0.009.Find a 95% confidence interval for the proportion of teenagers with some hearing loss.Round your answers to two decimal places.The 95% confidence interval is to .
Fuel consumption of taxis at an unnamed taxi rank follows a normal distribution with an average of 15 liters / 100km and the standard deviation of 5 liters / 100km. Nonni randomly selects 12 taxis from the station and examines the average consumption of these 12 cars. What is the standard error of average consumption? 1. 5 12 2. V5 3. 5 12 V12
Breaking Strength of Cable A special cable has a breaking strength of 800 pounds. The standard deviation of the population is 12 pounds. A researcher selects a sample of 23 cables and finds that the average breaking strength is 793 pounds. Can he reject the claim that the breaking strength is 800 pounds? Use the P-value method with a 0.05 level of significance. Assume that the variable is normally distributed. Use a graphing calculator. Part: 0/4 Part 1 of 4 (a) State the hypotheses and Identify the claim. Ho (Choose one) H₂: (Choose one) This hypothesis test is a (Choose one) test. 000-0 H G 民留〗f g E
The ability to determine the age of some individuals can be difficult if there are not quality government records of birth. Bone growth takes place at the growth plates at the end of long bones. Once all growth plates fuse, growth stops, and an individual is considered a biological adult. The age at which growth plates fuse for males is approximately normally distributed with a mean of 19 years and a standard deviation of 15.1 months. Complete parts (a) through (d). e this (a) What is the probability a male's growth plates fuse after age 21? The probability a male's growth plates fuse after age 21 is (Round to four decimal places as needed.) View an example Get more help. 4 CE 4 PrtScn Home End F10 PgUp Clear all ^O S ↓ PgDn Check answer 12:55 PM 11/21/2022
The number of peanuts in a 16 ounce can of nut munchies is normally distributed with a mean of 93.6 and a standard deviation of 4.2 peanuts the number of peanuts in a 20 ounce can of gone nuts is normally distributed with a mean of 111.8 and a standard deviation of 3.4 peanuts. (a) Carmen purchased a 16 ounce can of nut munchies and counted 100 peanuts what is the Z score for this can of peanuts? (b) Angelo purchased a 20 ounce can of gone nuts and counted 116 peanuts what is the Z score for this can of peanuts? (c) Carmen declares that purchase purchasing her can of nut munchies with 100 peanuts is less likely than Angelo purchasing a can of gone nuts with 116 peanuts is Carmen statement correct? Use the definition of a Z score to support or refute Carmen's claim.