Copper and aluminum are being considered for a high-voltage transmission line that must carry a current of 68.9 A. The resistance per unit length is to be 0.132 0/km. The densities of copper and aluminum are 8960 and 2600 kg/m³, respectively. Compute (a) the magnitude J of the current density and (b) the mass per unit length À for a copper cable and (c) J and (d) À for an aluminum cable. (a) Number i (b) Number i IN (c) Number (d) Number i Units Units Units Units

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
icon
Related questions
Question
**Problem Statement:**

Copper and aluminum are being considered for a high-voltage transmission line that must carry a current of 68.9 A. The resistance per unit length is to be 0.132 Ω/km. The densities of copper and aluminum are 8960 and 2600 kg/m³, respectively. Compute the following:

(a) The magnitude \( J \) of the current density for a copper cable.
(b) The mass per unit length \( \lambda \) for a copper cable.
(c) The magnitude \( J \) of the current density for an aluminum cable.
(d) The mass per unit length \( \lambda \) for an aluminum cable.

**Inputs for Your Calculations:**

(a) \[\text{Number}\]
Units [ _select units_ ]

(b) \[\text{Number}\]
Units [ _select units_ ]

(c) \[\text{Number}\]
Units [ _select units_ ]

(d) \[\text{Number}\]
Units [ _select units_ ]

**Explanation:**

In mathematical terms, the current density \( J \) is given by the formula:

\[ J = \frac{I}{A} \]

where:
- \( I \) is the current (68.9 A in this case).
- \( A \) is the cross-sectional area of the cable.

Furthermore, the mass per unit length \( \lambda \) is determined by:

\[ \lambda = \rho \cdot A \]

where:
- \( \rho \) is the density of the material.
- \( A \) is the cross-sectional area of the cable, which can be derived from the resistance and the electrical properties of the materials, using:

\[ R = \frac{\rho_{\text{electrical}} \cdot l}{A} \]

where:
- \( \rho_{\text{electrical}} \) is the resistivity of the material.
- \( l \) is the length of the cable.
- \( R \) is the resistance per unit length (0.132 Ω/km).

Make sure to use appropriate units and conversion factors in your calculations. 

**Note:**

There are no graphs or diagrams in this image. The problem requires performing a series of calculations with the information provided.
Transcribed Image Text:**Problem Statement:** Copper and aluminum are being considered for a high-voltage transmission line that must carry a current of 68.9 A. The resistance per unit length is to be 0.132 Ω/km. The densities of copper and aluminum are 8960 and 2600 kg/m³, respectively. Compute the following: (a) The magnitude \( J \) of the current density for a copper cable. (b) The mass per unit length \( \lambda \) for a copper cable. (c) The magnitude \( J \) of the current density for an aluminum cable. (d) The mass per unit length \( \lambda \) for an aluminum cable. **Inputs for Your Calculations:** (a) \[\text{Number}\] Units [ _select units_ ] (b) \[\text{Number}\] Units [ _select units_ ] (c) \[\text{Number}\] Units [ _select units_ ] (d) \[\text{Number}\] Units [ _select units_ ] **Explanation:** In mathematical terms, the current density \( J \) is given by the formula: \[ J = \frac{I}{A} \] where: - \( I \) is the current (68.9 A in this case). - \( A \) is the cross-sectional area of the cable. Furthermore, the mass per unit length \( \lambda \) is determined by: \[ \lambda = \rho \cdot A \] where: - \( \rho \) is the density of the material. - \( A \) is the cross-sectional area of the cable, which can be derived from the resistance and the electrical properties of the materials, using: \[ R = \frac{\rho_{\text{electrical}} \cdot l}{A} \] where: - \( \rho_{\text{electrical}} \) is the resistivity of the material. - \( l \) is the length of the cable. - \( R \) is the resistance per unit length (0.132 Ω/km). Make sure to use appropriate units and conversion factors in your calculations. **Note:** There are no graphs or diagrams in this image. The problem requires performing a series of calculations with the information provided.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 4 steps with 13 images

Blurred answer
Knowledge Booster
DC circuits
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
College Physics
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
University Physics (14th Edition)
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
Introduction To Quantum Mechanics
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
Physics for Scientists and Engineers
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley
College Physics: A Strategic Approach (4th Editio…
College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON