**Problem Statement:**A proton beam in an accelerator carries a current of 125 μA. If the beam is incident on a target, how many protons strike the target in a period of 23.0 seconds?**Explanation:**This problem involves calculating the number of protons striking a target based on the current carried by a proton beam and the duration of time over which the beam is incident on the target. Here, the current (I) is given as 125 microamperes (μA), and the time (t) is 23.0 seconds. **Note:** The solution involves using the relationship between current, charge, and time, where current is the rate of charge flow. Since the charge of a single proton is known, you can calculate the total number of protons.

Current is defined as the flow of charges. Whenever there is a motion of charged particles there will be a current flow. The magnitude of the current flow will depend on the magnitude of the charge and the time the charge flow takes place. It is given by, I=Qt Here Q is the charge and t is the time.The objective is to calculate the number of protons in the given beam. Given the proton beam carries a current. We know the current is given by, I=Qt Thus the charge carried will be given by Q=It Substitute I as 125 μA and t as 23 s. Q=(125 μA)(10−6 A⋅μA−1)(23 s)=2.875×10−3 C Thus the total charge on the beam will be 2.875 × 10-3 C. Now, each proton will have a charge of 1.6 × 10-19 C. Thus the total number of protons in 2.875 × 10-3 C of charge will be, n=2.875×10−3 C1.6×10−19 C=1.796×1016n=1.796×1016 Thus the proton beam will have around 1.796 × 1016 protons.1.796 × 1016 protons

Answered: A proton beam in an accelerator carries…

A proton beam in an accelerator carries a current of 125 μA. If the beam is incident on a target, how many protons strike the target in a period of 23.0 s?