**Problem Statement:**An aluminum wire having a cross-sectional area equal to \(3.10 \times 10^{-6} \, \text{m}^2\) carries a current of \(6.00 \, \text{A}\). The density of aluminum is \(2.70 \, \text{g/cm}^3\). Assume each aluminum atom supplies one conduction electron per atom. Find the drift speed of the electrons in the wire.[Input Box for Answer]**Hint:**The equation for drift velocity includes the number of charge carriers per volume, which in this case is equal to the number of atoms per volume. How do you calculate that if you know the density and the atomic weight of aluminum? (Answer in mm/s)

Answered: Image /qna-images/answer/ef3d572e-f7d8-46c2-8703-a8c70edaf238.jpg

Answered: An aluminum wire having a…

Similar questions

A copper wire of cross-sectional area 1.00 mm2 has a current of 7.40 A flowing along its length. What is the drift speed of the conduction electrons? Assume 1.30 conduction electrons per copper atom. The mass density of copper is 9.00 g/cm3 and its molar mass is 64.0 g/mol. 0.00041 * mm/s
An aluminum wire 1.291 mm in diameter (16-gauge) carries a current of 3 amps. Overall Hint a. What is the number density of charge carriers (electrons) in the wire? Hint for (a) 1 The number density of electrons in the wire is m³ (Use "E" notation to enter your answer in scientific notation. For example, to enter 3.14 × 10¹2, enter "3.14E12".) b. What is the magnitude of the drift velocity of the electrons? Hint for (b) The drift velocity of the electrons is va = m/s. c. What would be the drift velocity if the same gauge copper were used instead of aluminum? Hint for (c) For the same gauge copper wire, the drift velocity would be va - m/s. There is a disconnect between how small drift velocities are and how quickly electrical signals travel through wires (nearly at the speed of light). For the moment, treat the two as completely unrelated to each other.
A material is formed into a long rod with a square cross-section 0.50 cm on each side. When a 100 V voltage is applied across a 20 m length of the rod, a 5.0 A current is carried. a) What is the resistivity of the material? ρ = _______ Ω m b) Is the material a conductor, an insulator, or a semiconductor?
m An aluminum wire having a cross-sectional area equal to 2.10 x 107 -6 electron per atom. Find the drift speed of the electrons in the wire. mm/s Need Help? Read It carries a current of 7.00 A. The density of aluminum is 2.70 g/cm³. Assume each aluminum atom supplies one conduction
The magnitude J of the current density in a certain wire with a circular cross section of radius R = 2.09 mm is given by J = (3.20 × 108),², with J in amperes per square meter and radial distance r in meters. What is the current through the outer section bounded by r = 0.927R and r = R? Number i Units
A current of 1.6 A flows for 8.9 s through a conductor. Calculate the number of electrons that pass through a point in the conductor during this time. Answer format: 1.2e+20. (e+20 is same as x10^20)
The figure below represents a section of a circular conductor of nonuniform diameter carrying a current of I = 5.30 A. The radius of cross-section A1 is r1 = 0.510 cm. What is the magnitude (A/m2) of the current density across A1? Since the radius r2 at A2 is larger than the radius r1 at A1. will the current and current density at A2 larger, smaller, or the same? Assume A2 = 5A1. What is the radius, the current, and the current density at A2?
An electrical conductor designed to carry large currents has a circular cross section 2.40 mm in diameter and is 14.8 m long. The resistance between its ends is 0.107 2 Part A What is the resistivity of the material? ? p= Submit Request Answer Part B If the electric field magnitude in the conductor is 1.29 V/m. what is the total current? ? I = Part C If the material has 8,5 x 1025 free electrons per cubic meter, find the average drift speed under the conditions of part B. VO AE m/s Submit Reguest Answt
A copper wire of cross-sectional area 1.40 mm² has a current of 3.90 A flowing along its length. What is the drift speed of the conduction electrons? Assume 1.30 conduction electrons per copper atom. The mass density of copper is 9.00 g/cm³ and its molar mass is 64.0 g/mol. mm/s
Solve it correctly please. I will rate accordingly.
Problem 7 A cylindrical platinum wire is 0.0644 mm in diameter and 1.05 m in length. The wire carries a 1.05 A current. Assume there is one free electron (q = -1.602x10-19 C) per platinum atom. Avogadro's number is 6.022x1023 atoms per mol. Platinum has a density of 21.5 g/cm³, a molar mass of 195 g/mol, and a resistivity of 10.6x10-8 Qm. (a) Find the the current density (j), in units of A/m². (b) Find the number density of free electrons (n), in units of m-3. (c) Find the drift velocity of electrons in the wire (va), in units of m/s. (d) Find the magnitude of the electric field in the wire, in units of N/C. (e) Find the potential difference across the wire, in units of Volts.
With a potential difference of 4V across a wire of length 5m and cross section area 1x10-6 m2 there is found to be a current of 12A flowing in the wire. What is the conductivity of the wire? Select one: a. 1.5×107 Siemens b. 9.6×106 Siemens c. 6×10-7 Siemens d. 1.66×107 Siemens

SEE MORE QUESTIONS