Cooling of Cans of Potato Soup After Thermal Processing. A total of 1500 cans of potato soup undergo thermal processing in a retort at 240°F. The cans are then cooled to 100°F in the retort before being removed from the retort by cooling water, which enters at 75°F and leaves at 85 F. Calculate the Ib of cooling water needed. Each can of soup contains 1.0 lb of liquid soup and the empty metal can weighs 0.16 lb. The mean heat capacity of the soup is 0.94 btu/lbm. F and that of the metal can is 0.12 btu/lbm. °F. A metal rack or basket which is used to hold the cans in the retort weighs 350 lb and has a heat capacity of 0.12 btu/lbm.F. Assume that the metal rack is cooled from 240°F to 85°F, the temperature of the outlet water. The amount of heat removed from the retort walls in cooling from 240 to 100°F is 10000 btu. Radiation loss from the retort during cooling is estimated as 5000 btu.

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