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Convex Lenses When an object is placed at a distance d, from a lens of focal length f, and d, is greater than f, the rays hitting the lens will form a real image on the other side, at a distance d; from the lens. The object distance do, image distance d, and focal length f are related by the "Thin Lens Equation": 1 1 1 %3D do di The height of the image h; is usually different than the height of the original object ho. The factor by which the image is bigger than the object is called the Magnification M of the image. The magnification depends on the distances d, and d; if the image is farther from the lens than the object, it will be bigger than the object. hị M = ho dį do If the magnification is positive, the image is "right side up"; if it is negative, the image is upside down or "inverted." In this exercise, you will use the above equations to see what happens to the image as you move an object closer and closer to the lens. We are looking for patterns, to see how the variables change in relation to each other. Directions: Here are some practice problems to make you familiar with these concepts. Please review the following. An object is placed at four different distances from a convex lens with f = 20.0 cm: a) d. = 60.0 cm b) do = 50.0 cm c) do = 40.0 cm d) do = 30.0 cm %3D 1. For each distance, calculate the image distance d;.

Convex Lenses When an object is placed at a distance d, from a lens of focal length f, and d, is greater than f, the rays hitting the lens will form a real image on the other side, at a distance d; from the lens. The object distance do, image distance d, and focal length f are related by the "Thin Lens Equation": 1 1 1 %3D do di The height of the image h; is usually different than the height of the original object ho. The factor by which the image is bigger than the object is called the Magnification M of the image. The magnification depends on the distances d, and d; if the image is farther from the lens than the object, it will be bigger than the object. hị M = ho dį do If the magnification is positive, the image is "right side up"; if it is negative, the image is upside down or "inverted." In this exercise, you will use the above equations to see what happens to the image as you move an object closer and closer to the lens. We are looking for patterns, to see how the variables change in relation to each other. Directions: Here are some practice problems to make you familiar with these concepts. Please review the following. An object is placed at four different distances from a convex lens with f = 20.0 cm: a) d. = 60.0 cm b) do = 50.0 cm c) do = 40.0 cm d) do = 30.0 cm %3D 1. For each distance, calculate the image distance d;.

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Convex Lenses When an object is placed at a distance d, from a lens of focal length f, and d, is greater than f, the rays hitting the lens will form a real image on the other side, at a distance d; from the lens. The object distance do, image distance d;, and focal length f are related by the "Thin Lens Equation": 1 1 1 %3D do di The height of the image h; is usually different than the height of the original object ho. The factor by which the image is bigger than the object is called the Magnification M of the image. The magnification depends on the distances d, and d; if the image is farther from the lens than the object, it will be bigger than the object. di hị M = ho do If the magnification is positive, the image is "right side up"; if it is negative, the image is upside down or "inverted." In this exercise, you will use the above equations to see what happens to the image as you move an object closer and closer to the lens. We are looking for patterns, to see how the variables change in relation to each other. Directions: Here are some practice problems to make you familiar with these concepts. Please review the following. An object is placed at four different distances from a convex lens with f = 20.0 cm: a) do = 60.0 cm b) do = 50.0 cm c) do = 40.0 cm d) do = 30.0 cm %3D %3D 1. For each distance, calculate the image distance d;.
Transcribed Image Text:Convex Lenses When an object is placed at a distance d, from a lens of focal length f, and d, is greater than f, the rays hitting the lens will form a real image on the other side, at a distance d; from the lens. The object distance do, image distance d;, and focal length f are related by the "Thin Lens Equation": 1 1 1 %3D do di The height of the image h; is usually different than the height of the original object ho. The factor by which the image is bigger than the object is called the Magnification M of the image. The magnification depends on the distances d, and d; if the image is farther from the lens than the object, it will be bigger than the object. di hị M = ho do If the magnification is positive, the image is "right side up"; if it is negative, the image is upside down or "inverted." In this exercise, you will use the above equations to see what happens to the image as you move an object closer and closer to the lens. We are looking for patterns, to see how the variables change in relation to each other. Directions: Here are some practice problems to make you familiar with these concepts. Please review the following. An object is placed at four different distances from a convex lens with f = 20.0 cm: a) do = 60.0 cm b) do = 50.0 cm c) do = 40.0 cm d) do = 30.0 cm %3D %3D 1. For each distance, calculate the image distance d;.
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