A bike rider approaches a hill with a speed of 8.50 m/s. The total mass of the bike and rider is 85-kg a. Find the kinetic energy of the bike and rider. ッ7o.6 JV The rider coast up the hill. Assuming there is no friction; at what height will the bike come to a stop? KE -h 307026 mg (85)(9.8) 354 J c. Does your answer depend on the mass of the bike and rider? Explain.
Kinematics
A machine is a device that accepts energy in some available form and utilizes it to do a type of work. Energy, work, or power has to be transferred from one mechanical part to another to run a machine. While the transfer of energy between two machine parts, those two parts experience a relative motion with each other. Studying such relative motions is termed kinematics.
Kinetic Energy and Work-Energy Theorem
In physics, work is the product of the net force in direction of the displacement and the magnitude of this displacement or it can also be defined as the energy transfer of an object when it is moved for a distance due to the forces acting on it in the direction of displacement and perpendicular to the displacement which is called the normal force. Energy is the capacity of any object doing work. The SI unit of work is joule and energy is Joule. This principle follows the second law of Newton's law of motion where the net force causes the acceleration of an object. The force of gravity which is downward force and the normal force acting on an object which is perpendicular to the object are equal in magnitude but opposite to the direction, so while determining the net force, these two components cancel out. The net force is the horizontal component of the force and in our explanation, we consider everything as frictionless surface since friction should also be calculated while called the work-energy component of the object. The two most basics of energy classification are potential energy and kinetic energy. There are various kinds of kinetic energy like chemical, mechanical, thermal, nuclear, electrical, radiant energy, and so on. The work is done when there is a change in energy and it mainly depends on the application of force and movement of the object. Let us say how much work is needed to lift a 5kg ball 5m high. Work is mathematically represented as Force ×Displacement. So it will be 5kg times the gravitational constant on earth and the distance moved by the object. Wnet=Fnet times Displacement.
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Corrections
Conservation of Energy
tions: Read each of the following statements/questions. Answer them correctly and box your final answer.
A large chuck of ice with mass 15.0-kg falls from a roof 8.00 m above the ground.
a. Find the kinetic energy of the ice when it reaches the ground.
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h=-8
9-9-8
b. What is the speed of the ice when it reaches the ground?
2aM4= 3ンて
v? 2 KE
ord to s2ed prli of svilslon 229220bo 5 Kg
2. A bike rider approaches a hill with a speed of 8.50 m/s. The total mass of the bike and rider is 85-kg
VE 1 (1175J)
?KE y
a. Find the kinetic energy of the bike and rider.
70.6 JV
The rider coast up the hill. Assuming there is no friction; at what height will the bike come to a
stop? KE -h
mg
307026
354J
(85)(9.8)
c.
Does your answer depend on the mass of the bike and rider? Explain.
Yes
1/2
3. Tarzan, mass 85-kg, swings down from a tree limb on the end of a 20 m vine. His feet touch the ground
4.0 m below the limb.
a. How fast is Tarzan moving when he reaches the ground?
カニ85 イg
2X 9.8X4
V-8.87m/s
. Does your answer depend on Tarzan's mass?
velocitg
is given by equoliond
Poes your answer depend on the length of the vine?
ve loci by is given by equalion Is, yhich is
inder
VoF Lengt h of
from rest at the top of a 45.0 m hill; skies down a 30.0° incline into a valley, and contin
Both hill heights are measured from the valley floor. Assume you can neglect frictio
i poles.
is the skier moving at the bottom of the valley?
ier's speed at the top of the next hill?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc7751a5a-4a85-487a-845a-c3c8bd69aa51%2F4eded354-b11f-4617-bcee-e832ccbf66d3%2Flrx098_processed.jpeg&w=3840&q=75)
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