**Interconverting Compound SI Units**Convert the following measurement.\[ 79 \, \text{mg/dL} = \, \square \, \text{g/L} \]To convert from mg/dL to g/L, use the following conversion factors:1 mg = 0.001 g1 dL = 0.1 LTherefore, to convert \( 79 \, \text{mg/dL} \) to \(\text{g/L}\):\[ 79 \, \text{mg/dL} \times \frac{0.001 \, \text{g}}{1 \, \text{mg}} \times \frac{1 \, \text{dL}}{0.1 \, \text{L}} \]This simplifies to:\[ 79 \times \frac{0.001}{0.1} \, \text{g/L} = 7.9 \, \text{g/L} \]Thus, the measurement converts to \( 7.9 \, \text{g/L} \).

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Answered: Convert the following measurement. 79 •…

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Convert the following measurement. 79 • =ㅁ를 mg dL

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

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Question

**Interconverting Compound SI Units**

Convert the following measurement.

\[ 79 \, \text{mg/dL} = \, \square \, \text{g/L} \]

To convert from mg/dL to g/L, use the following conversion factors:

1 mg = 0.001 g
1 dL = 0.1 L

Therefore, to convert \( 79 \, \text{mg/dL} \) to \(\text{g/L}\):

\[ 79 \, \text{mg/dL} \times \frac{0.001 \, \text{g}}{1 \, \text{mg}} \times \frac{1 \, \text{dL}}{0.1 \, \text{L}} \]

This simplifies to:

\[ 79 \times \frac{0.001}{0.1} \, \text{g/L} = 7.9 \, \text{g/L} \]

Thus, the measurement converts to \( 7.9 \, \text{g/L} \).

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