Convert 0.301 mol of ammonium (NH) ions to equivalents. 0.301 mol NH = Convert 1.95 mol of sulfite (SO3) ions to equivalents. 1.95 mol SO3- = Eq Eq

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Chapter1: Chemical Foundations
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Answer the above conventions

**Convert 0.301 mol of ammonium (NH₄⁺) ions to equivalents.**

0.301 mol NH₄⁺ = [_____] Eq

---

**Convert 1.95 mol of sulfite (SO₃²⁻) ions to equivalents.**

1.95 mol SO₃²⁻ = [_____] Eq

---

*Explanation for Educational Context:*

In the given exercises, we are asked to convert moles of ions into equivalents. The concept of equivalents is used in chemistry to express the reactive capacity of a molecule. 

- For the ammonium ion (NH₄⁺), which has a charge of +1, each mole of NH₄⁺ equals one equivalent.
- For the sulfite ion (SO₃²⁻), which has a charge of -2, each mole of SO₃²⁻ equals two equivalents. To find the equivalents, multiply the number of moles by the absolute value of the ion’s charge. 

This conversion is crucial for understanding reactions in solution, particularly in the context of titrations and ion-exchange processes.
Transcribed Image Text:**Convert 0.301 mol of ammonium (NH₄⁺) ions to equivalents.** 0.301 mol NH₄⁺ = [_____] Eq --- **Convert 1.95 mol of sulfite (SO₃²⁻) ions to equivalents.** 1.95 mol SO₃²⁻ = [_____] Eq --- *Explanation for Educational Context:* In the given exercises, we are asked to convert moles of ions into equivalents. The concept of equivalents is used in chemistry to express the reactive capacity of a molecule. - For the ammonium ion (NH₄⁺), which has a charge of +1, each mole of NH₄⁺ equals one equivalent. - For the sulfite ion (SO₃²⁻), which has a charge of -2, each mole of SO₃²⁻ equals two equivalents. To find the equivalents, multiply the number of moles by the absolute value of the ion’s charge. This conversion is crucial for understanding reactions in solution, particularly in the context of titrations and ion-exchange processes.
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