Continuing with the same setup as above, where you connect a 6 Q resistor and a 12 Q resistor in series to a 9 V battery. Find the potential difference, V2, across the 6 Q resistor in Volts.

Introductory Circuit Analysis (13th Edition)
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Author:Robert L. Boylestad
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•V=IR
V.
I =
R =
• Series
3=
ns
Iroa = I1 = I½
Vrot = Vị + V2
RTot = R1 + R2
Parallel
Irot = I1 + I2
VTot = Vi = V2
1
R
R1 R2
R1+R2
RTot
R2
RTot
Transcribed Image Text:•V=IR V. I = R = • Series 3= ns Iroa = I1 = I½ Vrot = Vị + V2 RTot = R1 + R2 Parallel Irot = I1 + I2 VTot = Vi = V2 1 R R1 R2 R1+R2 RTot R2 RTot
Continuing with the same setup as above, where you connect
a 6 Q resistor and a 12 Q resistor in series to a 9 V battery.
Find the potential difference, V2, across the 6 Q resistor in
Volts.
Hint: VTot = V1 = V2.
RTot
ITot
R1
BAT1
R2
12 Q
9 V
Transcribed Image Text:Continuing with the same setup as above, where you connect a 6 Q resistor and a 12 Q resistor in series to a 9 V battery. Find the potential difference, V2, across the 6 Q resistor in Volts. Hint: VTot = V1 = V2. RTot ITot R1 BAT1 R2 12 Q 9 V
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