In Step 3, what is the potential difference across D2 after the jumper wire is connected? O Approximately 1.8V, because my LED is still lit and the jumper wire is not properly connected. OL, because I am not using the correct meter settings. Approximately 5V, because I am somehow measuring across the whole path instead of just D2. 0.0 mV, because the LED is not lit and the component leads are connected to each other by the jumper wire.

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Author:Robert L. Boylestad
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In step 3, what is the potential difference across D2 after the jumper wire is connected
STEP 3
Add a jumper wire to the circuit, in parallel
with D2, as illustrated in this schematic:
D1
R1
D2
Red
330 Q
Blue
PSB
5 V
You will know it is connected correctly
because D2 is shorted and goes out, causing
D1 to become brighter.
What will the voltage be across D2 now
that it has been shorted?
If there is no potential difference across
D2, then it makes sense that no current
will flow through it.
• With the jumper connecting the high side
of D2 directly to the breadboard ground
rail, what will be the new potential of tha
iunction point, relative to ground?
Transcribed Image Text:STEP 3 Add a jumper wire to the circuit, in parallel with D2, as illustrated in this schematic: D1 R1 D2 Red 330 Q Blue PSB 5 V You will know it is connected correctly because D2 is shorted and goes out, causing D1 to become brighter. What will the voltage be across D2 now that it has been shorted? If there is no potential difference across D2, then it makes sense that no current will flow through it. • With the jumper connecting the high side of D2 directly to the breadboard ground rail, what will be the new potential of tha iunction point, relative to ground?
In Step 3, what is the potential
difference across D2 after the jumper
wire is connected?
Approximately 1.8V, because my LED is still lit
and the jumper wire is not properly
connected.
OL, because I am not using the correct meter
settings.
O Approximately 5V, because I am somehow
measuring across the whole path instead of
just D2.
0.0 mV, because the LED is not lit and the
component leads are connected to each other
by the jumper wire.
Transcribed Image Text:In Step 3, what is the potential difference across D2 after the jumper wire is connected? Approximately 1.8V, because my LED is still lit and the jumper wire is not properly connected. OL, because I am not using the correct meter settings. O Approximately 5V, because I am somehow measuring across the whole path instead of just D2. 0.0 mV, because the LED is not lit and the component leads are connected to each other by the jumper wire.
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