Continue solving for the reactions. Calculate the reactions at each support. Draw the shear, moment, elastic curve and axial force diagram.
Continue solving for the reactions. Calculate the reactions at each support. Draw the shear, moment, elastic curve and axial force diagram.
Materials Science And Engineering Properties
1st Edition
ISBN:9781111988609
Author:Charles Gilmore
Publisher:Charles Gilmore
Chapter8: Engineering Materials
Section: Chapter Questions
Problem 85CQ
Related questions
Question
Pls. Continue solving for the reactions.
Calculate the reactions at each support. Draw the shear, moment, elastic curve and axial force diagram.
![3.) Fixed at A, Hinge at E, Internal Hinge at B.D.F.
2 GOIN
4.0m
<- Ax
8.0m
Subst. →
Σ ΜΕ ΤΟ G
Ay (10) + MA-25 (5) + 15(s) = 0
Ay (10) + MA = 50
MA= 50-10 Ay →
RIOM
- 4 Ay +50=0
Ay = 12.S KN
@ba
- 0
MA= -15
MA- 75 KN.M
@ 0
MA = 50-10AY
MA= 50-10(12.5)
25 kN
↓c
3 Ay+ 4Ax + (50-10 Ay)-D
3 Ay - 10 Ay +4 Ax +50=0
- TAY + 4 Ax +50=0 (20)
Subst →
7 Ay + 4 Ax + (50-10Ay) - 50
7Ay-10Ay +4Ax +50=50
-3Ay + 4 Ax = 0→Ba
@2a-3a
- TAY SAX50=0
- 3 Ay+gAx=0
-3 Ay+ 4AX=0
-3(12.6) + 4 Ax=0
Ax=9,315 kN
2.0m
D₂
3.0m
t
10kN/m
TEX
Fy
3.0m
@ AB
Ay
MA
@ A B C D
-Ax
AAX
Ay
15 KN
Ja
2.0m
B, 4 Bx
Toy
25kN
C
ΣMB- 0 Co³ +
Ay (3) + Ax(4) +MA-O
3Ay +4 Ax +MA-0-6
-DX
P↑
Dy
ZMp=0 C² +
Ay(1) + Ax(4) + MA-25 (2)=0
1 Ay + 4AX + MA= 50 -13](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9b6862bb-8a87-438c-b7e0-14a7aff7e0be%2F31b54fe1-eccb-4c85-b160-3dd4efb871fc%2F6e7dafr_processed.jpeg&w=3840&q=75)
Transcribed Image Text:3.) Fixed at A, Hinge at E, Internal Hinge at B.D.F.
2 GOIN
4.0m
<- Ax
8.0m
Subst. →
Σ ΜΕ ΤΟ G
Ay (10) + MA-25 (5) + 15(s) = 0
Ay (10) + MA = 50
MA= 50-10 Ay →
RIOM
- 4 Ay +50=0
Ay = 12.S KN
@ba
- 0
MA= -15
MA- 75 KN.M
@ 0
MA = 50-10AY
MA= 50-10(12.5)
25 kN
↓c
3 Ay+ 4Ax + (50-10 Ay)-D
3 Ay - 10 Ay +4 Ax +50=0
- TAY + 4 Ax +50=0 (20)
Subst →
7 Ay + 4 Ax + (50-10Ay) - 50
7Ay-10Ay +4Ax +50=50
-3Ay + 4 Ax = 0→Ba
@2a-3a
- TAY SAX50=0
- 3 Ay+gAx=0
-3 Ay+ 4AX=0
-3(12.6) + 4 Ax=0
Ax=9,315 kN
2.0m
D₂
3.0m
t
10kN/m
TEX
Fy
3.0m
@ AB
Ay
MA
@ A B C D
-Ax
AAX
Ay
15 KN
Ja
2.0m
B, 4 Bx
Toy
25kN
C
ΣMB- 0 Co³ +
Ay (3) + Ax(4) +MA-O
3Ay +4 Ax +MA-0-6
-DX
P↑
Dy
ZMp=0 C² +
Ay(1) + Ax(4) + MA-25 (2)=0
1 Ay + 4AX + MA= 50 -13
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Step 1: Introducing Given Data
VIEWStep 2: Calculation of reactions at E
VIEWStep 3: Calculation of reactions at A
VIEWStep 4: Calculation of Internal forces for part AB
VIEWStep 5: Calculation of Internal forces for part BCD
VIEWStep 6: Calculation of Internal forces for part FG
VIEWStep 7: Calculation of Internal forces for part DF
VIEWStep 8: Calculation of Axial forces for member DE, DF & EF
VIEWStep 9: Calculation of Internal forces for part DE & EF
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