Construct the indicated confidence interval for the population mean μ using the t-distribution. Assume the population is normally distributed. c=0.98, x=13.4, s=0.73, n= 18
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- Cell Phone Call Lengths The average local cell phone call length was reported to be 2.39 minutes. A random sample of 24 phone calls showed an average of 2.83 minutes in length with a standard deviation of 0.9 minutes. At =α0.01, can it be concluded that the average differs from the population average? Assume that the population is approximately normally distributed. a. State the hypotheses and identify the claim H0= (claim or not claim) H1= (claim or not claim) This hypothesis test is a (one tailed or two tailed) test Critical value(s)= t= (Reject or do not reject) the null hypothesis is there enough evidence to support the claim?An IQ test is designed so that the mean is 100 and the standard deviation is 10 for the population of normal adults. Find the sample size necessary to estimate the mean IQ score of statistics students such that it can be said with 99% confidence that the sample mean is within 8 IQ points of the true mean. Assume that σ=10 and determine the required sample size.Find SAT Quartiles. SAT scores are reported on a scale from 600 to 2400. The mean is 1498 and the standard deviation is 316. The quartiles of any distribution are the values with cumulative proportions 0.25, and 0.75. What are the quartiles of the distribution of SAT scores?
- Assume the samples are random and independent, the populations are nomally distributed, and the population variances are equal. The table available below shows the prices (in dollars) for a sample of automobile batteries. The prices are classified according to battery type. At a = 0.10, is there enough evidence to conclude that at least one mean battery price is different from the others? Complete parts (a) through (e) below. E Click the icon to view the battery cost data. (a) Let u. 2 Ha represent the mean prices for the group size 35, 65, and 24/24F respectively. Identify the claim and state Ho and H.. Ho: H - X Cost of batteries by type The claim the V hypothesis. Group size 35 Group size 65 Group size 24/ 24F 91 99 111 119 126 O 91 144 174 180 278 79 84 126 140 140 (b) Find the critical value, Fo. and identify the rejection region. The rejection region is F Fo, where Fo- (Round to two decimal places as needed.) (c) Find the test statistic F. F= (Round to two decimal places as…Assume the samples are random and independent, the populations are nomally distributed, and the population variances are equal. The table available below shows the prices (in dollars) for a sample of automobile batteries. The prices are classified according to battery type. At a = 0.10, is there enough evidence conclude that at least one mean battery price is different from the others? Complete parts (a) through (e) below. E Click the icon to view the battery cost data. (a) Let u1. P2. H3 represent the mean prices for the group size 35, 65, and 24/24F respectively. Identify the claim and state Ho and H. H Cost of batteries by type The claim is the V hypothesis. Group size 35 Group size 65 Group size 24/24F 101 111 121 124 D 146 173 182 278 124 140 141 89 (b) Find the critical value, Fo, and identify the rejection region. 90 79 84 The rejection region is F Fo, where Fo = (Round to two decimal places as needed.) (c) Find the test statistic F. Print Done F= (Round to two decimal places as…Interstate Speeds It has been reported that the standard deviation of the speeds of drivers on Interstate 75 near Findlay, Ohio, is 8 miles per hour for all vehicles. A driver feels from experience that this is very low. A survey is conducted, and for 29 drivers the standard deviation is 9.9 miles per hour. At =α0.10, is the driver correct? Assume the variable is normally distributed. State the hypotheses and identify the claim with the correct hypothesis. H0: H1: Claim or Not a Claim? This Hypothesis test is one-tailed or two-tailed? What is the Critical Value?
- Assume that a randomly selected subject is given a bone density test. Bone density test scores are normally distributed with a mean of 0 and a standard deviation of 1. Draw a graph and find P15, the 15th percentile. This is the bone density score separating the bottom 15% from the top 85%. How to get and what is the bone density score corresponding to P15 is ?Assume that a randomly selected subject is given a bone density test. Bone density test scores are normally distributed with a mean of 0 and a standard deviation of 1. Draw a graph and find P9, the 9th percentile. This is the bone density score separating the bottom 9% from the top 91%. Which graph represents P9? Choose the correct graph below.Assume the data set described is normally distributed with the given mean and standard deviation, and with n total values. Find the approximate number of data values that will fall in the given range. Mean-8 Standard deviation-1.5 n-45 Range: 6.5 to 9.5 In this case, we expect about 52 data values to fall between 6.5 and 9.5.
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