Construct an ICE table for the equilibrium reaction of the salt LINO₂P2 in water. For initial concentrations, write 0.090 M for the reactant and O M for both products. K, for HNO₂P2 = 9.55X10⁹. Which of the following statements is/are true? Multiple answers are possible. In the ICE table, the species with an equilibrium concentration of 0.090-x is LINO₂P2. In the ICE table, the species with an equilibrium concentration of x is H³O*. In the ICE table, the formula of the reactant is Li*. Dissolving this salt in water produces a basic solution. In the ICE table, one of the products is NO₂P₂.

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Construct an ICE table for the equilibrium reaction of the salt LINO₂P2 in water. For initial
concentrations, write 0.090 M for the reactant and O M for both products. K, for HNO₂P2 =
9.55X10⁹. Which of the following statements is/are true? Multiple answers are possible.
In the ICE table, the species with an equilibrium concentration of 0.090-x is LINO₂P2.
In the ICE table, the species with an equilibrium concentration of x is H³O*.
In the ICE table, the formula of the reactant is Li*.
Dissolving this salt in water produces a basic solution.
In the ICE table, one of the products is NO₂P2.
Transcribed Image Text:Construct an ICE table for the equilibrium reaction of the salt LINO₂P2 in water. For initial concentrations, write 0.090 M for the reactant and O M for both products. K, for HNO₂P2 = 9.55X10⁹. Which of the following statements is/are true? Multiple answers are possible. In the ICE table, the species with an equilibrium concentration of 0.090-x is LINO₂P2. In the ICE table, the species with an equilibrium concentration of x is H³O*. In the ICE table, the formula of the reactant is Li*. Dissolving this salt in water produces a basic solution. In the ICE table, one of the products is NO₂P2.
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