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Construct a pie graph for the relative frequency

Construct a pie graph for the relative frequency

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Construct a pie graph for the relative frequency

The data below are the height of 20 students in a class: 133 136 120 138 134 132 126 141 127 143 130 131 125 144 128 134 135 137 133 129 The highest value from the data is 120 The lowest value from the data is 144. Thus, the range of the data is, Range = H. V - L. V = 144 – 120 = 24 The number of classes can be calculated as: k = 1+3. 322 log N = 1 + 3. 322 log 20 = 5. 32 The class interval size can be calculate as: Range Number of classes 24 5 = 4.8 The frequency distribution table of the height of 20 students. Classes Frequency Class Mark Class Boundary Relative Frequency <cf 120-125 1. 122.5 119.5-125.5 1 126-131 7 128.5 125.5-131.5 35 8 132-137 8 134.5 131.5-137.5 40 16 138-143 3 140.5 137.5-143.5 15 19 144-149 1. 146.5 143.5-149.5 5 20 20
Transcribed Image Text:The data below are the height of 20 students in a class: 133 136 120 138 134 132 126 141 127 143 130 131 125 144 128 134 135 137 133 129 The highest value from the data is 120 The lowest value from the data is 144. Thus, the range of the data is, Range = H. V - L. V = 144 – 120 = 24 The number of classes can be calculated as: k = 1+3. 322 log N = 1 + 3. 322 log 20 = 5. 32 The class interval size can be calculate as: Range Number of classes 24 5 = 4.8 The frequency distribution table of the height of 20 students. Classes Frequency Class Mark Class Boundary Relative Frequency <cf 120-125 1. 122.5 119.5-125.5 1 126-131 7 128.5 125.5-131.5 35 8 132-137 8 134.5 131.5-137.5 40 16 138-143 3 140.5 137.5-143.5 15 19 144-149 1. 146.5 143.5-149.5 5 20 20
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