Construct a 99 % confidence interval for the difference between the mean lifetimes of two kinds of light bulbs, given that a random sample of 40 light bulbs of the first kind lasted on the average 41 hours of continuous use and 50 light bulbs of the second kind lasted on the average 40. hours of continuous. use. The population standard deviations are known to be o1 = 26 and o2 = 22. Solution For a = 0.06, we find from Table III that z0.03 = 94% confidence interval for µi – 1.88. Therefore, the I uz is 262 (418 - 402) – 1.88 · V 40. 222 < H1 - 42 50 262 222 + 40 < (418 – 402) +1.88 · 50

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Construct a 99 % confidence interval for the difference between the mean lifetimes
of two kinds of light bulbs, given that a random sample of 40 light bulbs of the
first kind lasted on the average 41 hours of continuous use and 50 light bulbs of
the second kind lasted on the average 40. hours of continuous. use. The population
standard deviations are known to be o1 = 26 and o2 = 22.
Solution For a = 0.06, we find from Table III that z0.03 =
94% confidence interval for µi –
1.88. Therefore, the
uz is
262
(418 - 402) – 1.88 ·
V 40.
222
< H1 - 42
50
262
222
+
40
< (418 – 402) +1.88 ·
50
Transcribed Image Text:Construct a 99 % confidence interval for the difference between the mean lifetimes of two kinds of light bulbs, given that a random sample of 40 light bulbs of the first kind lasted on the average 41 hours of continuous use and 50 light bulbs of the second kind lasted on the average 40. hours of continuous. use. The population standard deviations are known to be o1 = 26 and o2 = 22. Solution For a = 0.06, we find from Table III that z0.03 = 94% confidence interval for µi – 1.88. Therefore, the uz is 262 (418 - 402) – 1.88 · V 40. 222 < H1 - 42 50 262 222 + 40 < (418 – 402) +1.88 · 50
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