Construct a 95% confidence interval for mu 1 minus mu 2μ1−μ2 with the sample statistics for mean cholesterol content of a hamburger from two fast food chains and confidence interval construction formula below. Assume the populations are approximately normal with unequal variances. Stats x overbar 1 equals 123 mg comma s 1 equals 3.79 mg comma n 1 equals 20x1=123 mg, s1=3.79 mg, n1=20 x overbar 2 equals 87 mg comma s 2 equals 2.05 mg comma n 2 equals 15x2=87 mg, s2=2.05 mg, n2=15 ConfidenceConfidence interval wheninterval when variances arevariances are not equal left parenthesis x overbar 1 minus x overbar 2 right parenthesis minus t Subscript c Baseline StartRoot StartFraction s Subscript 1 Superscript 2 Over n 1 EndFraction plus StartFraction s Subscript 2 Superscript 2 Over n 2 EndFraction EndRoot less than mu 1 minus mu 2 less than left parenthesis x overbar 1 minus x overbar 2 right parenthesis plus t Subscript c Baseline StartRoot StartFraction s Subscript 1 Superscript 2 Over n 1 EndFraction plus StartFraction s Subscript 2 Superscript 2 Over n 2 EndFraction EndRootx1−x2−tcs21n1+s22n2<μ1−μ2<x1−x2+tcs21n1+s22n2 d.f. is the smaller of n 1n1minus−1 or n 2n2minus−1 Question content area bottom Part 1 Enter the endpoints of the interval. nothing less than mu 1 minus mu 2 less than nothingenter your response here<μ1−μ2<enter your response here Assume the populations are approximately normal with unequal variances.Assume the populations are approximately normal with unequal variances.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question

Construct a

95%

confidence interval for

mu 1 minus mu 2μ1−μ2

with the sample statistics for mean cholesterol content of a hamburger from two fast food chains and confidence interval construction formula below. Assume the populations are approximately normal with unequal variances.

Stats	x overbar 1 equals 123 mg comma s 1 equals 3.79 mg comma n 1 equals 20x1=123 mg, s1=3.79 mg, n1=20	x overbar 2 equals 87 mg comma s 2 equals 2.05 mg comma n 2 equals 15x2=87 mg, s2=2.05 mg, n2=15
ConfidenceConfidence interval wheninterval when variances arevariances are not equal	left parenthesis x overbar 1 minus x overbar 2 right parenthesis minus t Subscript c Baseline StartRoot StartFraction s Subscript 1 Superscript 2 Over n 1 EndFraction plus StartFraction s Subscript 2 Superscript 2 Over n 2 EndFraction EndRoot less than mu 1 minus mu 2 less than left parenthesis x overbar 1 minus x overbar 2 right parenthesis plus t Subscript c Baseline StartRoot StartFraction s Subscript 1 Superscript 2 Over n 1 EndFraction plus StartFraction s Subscript 2 Superscript 2 Over n 2 EndFraction EndRootx1−x2−tcs21n1+s22n2<μ1−μ2<x1−x2+tcs21n1+s22n2
d.f. is the smaller of n 1n1minus−1 or n 2n2minus−1