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Constants When two hydrogen atoms of mass m combine to form a diatomic hydrogen molecule (H2), the potential energy of the system after they combine is -A, where A is a positive quantity called the binding energy of the molecule. Part A Show that in a collision that involves only two hydrogen atoms, it is impossible to form an H2 molecule because momentum and energy cannot simultaneously be conserved. (Hint: If you can show this to be true in one frame of reference, then it is true in all frames of reference. Can you see why?) Essay answers are limited to about 500 words (3800 characters maximum, including spaces). 3800 Character(s) remaining Submit Request Answer Part B An H2 molecule can be formed in a collision that involves three hydrogen atoms. Suppose that before such a collision, each of the three atoms has speed 7000 m/s , and they are approaching at 120 ° angles so that at any instant, the atoms lie at the corners of an equilateral triangle. Find the speeds of the H2 molecule and of the single hydrogen atom that remains after the collision. The binding energy of H2 is A= 7.23 x 10 1ºJ, and the mass of the hydrogen atom is 1.67 x 10 2"kg. Enter your answers numerically separated by a comma. ? Vmolecule , Vatom = m/s

Constants When two hydrogen atoms of mass m combine to form a diatomic hydrogen molecule (H2), the potential energy of the system after they combine is -A, where A is a positive quantity called the binding energy of the molecule. Part A Show that in a collision that involves only two hydrogen atoms, it is impossible to form an H2 molecule because momentum and energy cannot simultaneously be conserved. (Hint: If you can show this to be true in one frame of reference, then it is true in all frames of reference. Can you see why?) Essay answers are limited to about 500 words (3800 characters maximum, including spaces). 3800 Character(s) remaining Submit Request Answer Part B An H2 molecule can be formed in a collision that involves three hydrogen atoms. Suppose that before such a collision, each of the three atoms has speed 7000 m/s , and they are approaching at 120 ° angles so that at any instant, the atoms lie at the corners of an equilateral triangle. Find the speeds of the H2 molecule and of the single hydrogen atom that remains after the collision. The binding energy of H2 is A= 7.23 x 10 1ºJ, and the mass of the hydrogen atom is 1.67 x 10 2"kg. Enter your answers numerically separated by a comma. ? Vmolecule , Vatom = m/s

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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what's the answer of part A and part B ?

Alternative Exercise 8.144: Binding Energy of the Hydrogen Molecule 22 of 29 Constants When two hydrogen atoms of mass m combine to form a diatomic hydrogen molecule (H2), the potential energy of the system after they combine is -A, where A is a positive quantity called the binding energy of the molecule. Part A Show that in a collision that involves only two hydrogen atoms, it is impossible to form an H2 molecule because momentum and energy cannot simultaneously be conserved. (Hint: If you can show this to be true in one frame of reference, then it is true in all frames of reference. Can you see why?) Essay answers are limited to about 500 words (3800 characters maximum, including spaces). 3800 Character(s) remaining Submit Request Answer Part B An H2 molecule can be formed in a collision that involves three hydrogen atoms. Suppose that before such a collision, each of the three atoms has speed 7000 m/s , and they are approaching at 120 ° angles so that at any instant, the atoms lie at the corners of an equilateral triangle. Find the speeds of the H2 molecule and of the single hydrogen atom that remains after the collision. The binding energy of H2 is A= 7.23 x 10 1ºJ, and the mass of the hydrogen atom is 1.67 × 10 2"kg. Enter your answers numerically separated by a comma. ΑΣφ ? Umolecule , Vatom = m/s
Transcribed Image Text:Alternative Exercise 8.144: Binding Energy of the Hydrogen Molecule 22 of 29 Constants When two hydrogen atoms of mass m combine to form a diatomic hydrogen molecule (H2), the potential energy of the system after they combine is -A, where A is a positive quantity called the binding energy of the molecule. Part A Show that in a collision that involves only two hydrogen atoms, it is impossible to form an H2 molecule because momentum and energy cannot simultaneously be conserved. (Hint: If you can show this to be true in one frame of reference, then it is true in all frames of reference. Can you see why?) Essay answers are limited to about 500 words (3800 characters maximum, including spaces). 3800 Character(s) remaining Submit Request Answer Part B An H2 molecule can be formed in a collision that involves three hydrogen atoms. Suppose that before such a collision, each of the three atoms has speed 7000 m/s , and they are approaching at 120 ° angles so that at any instant, the atoms lie at the corners of an equilateral triangle. Find the speeds of the H2 molecule and of the single hydrogen atom that remains after the collision. The binding energy of H2 is A= 7.23 x 10 1ºJ, and the mass of the hydrogen atom is 1.67 × 10 2"kg. Enter your answers numerically separated by a comma. ΑΣφ ? Umolecule , Vatom = m/s
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