A student begins at rest and then walks north at a speed of v₁ = 0.85 m/s. The student then turns south and walks at a speed of v2 = 0.33 m/s. Take north to be the positive direction. Refer to the figure. S m/s² N If it takes the student 1.2 s to reach the speed v₁, from rest, what is the magnitude, in meters per squared second, of the student's average acceleration during that time? davg =
A student begins at rest and then walks north at a speed of v₁ = 0.85 m/s. The student then turns south and walks at a speed of v2 = 0.33 m/s. Take north to be the positive direction. Refer to the figure. S m/s² N If it takes the student 1.2 s to reach the speed v₁, from rest, what is the magnitude, in meters per squared second, of the student's average acceleration during that time? davg =
College Physics
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Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Problem Statement:**
A student begins at rest and then walks north at a speed of \( v_1 = 0.85 \, \text{m/s} \). The student then turns south and walks at a speed of \( v_2 = 0.33 \, \text{m/s} \). Take north to be the positive direction. Refer to the figure.
**Illustration:**
An image depicts a student walking on a field with directional arrows indicating north (N) to the right and south (S) to the left.
**Question:**
If it takes the student 1.2 seconds to reach the speed \( v_1 \), from rest, what is the magnitude, in meters per second squared, of the student’s average acceleration during that time?
\[ a_{\text{avg}} = \, \text{______ m/s}^2 \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F38a9992d-9c05-40da-9474-aaafff450dc4%2F8886a565-c621-4ce8-b756-bcfb7b3e8799%2Fup2s0c6_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
A student begins at rest and then walks north at a speed of \( v_1 = 0.85 \, \text{m/s} \). The student then turns south and walks at a speed of \( v_2 = 0.33 \, \text{m/s} \). Take north to be the positive direction. Refer to the figure.
**Illustration:**
An image depicts a student walking on a field with directional arrows indicating north (N) to the right and south (S) to the left.
**Question:**
If it takes the student 1.2 seconds to reach the speed \( v_1 \), from rest, what is the magnitude, in meters per second squared, of the student’s average acceleration during that time?
\[ a_{\text{avg}} = \, \text{______ m/s}^2 \]
Expert Solution
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We know that average acceleration can be written as aavg=(vfinal-vinitial)/(time interval)
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