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- ver | Portal E Edulastic A app.edulastic.com/student/assessment/612d40e134150600096ede01/class/60ecbbe284e66e8d62a95cff/uta/61310195c7a5190009489400/itemld/612d40e13415060009... 1 SUBMIT A BOOKMARK X||凹||a Question 13/13 Scenario: 13 An ice skater is standing at rest next to the wall of the ice rink. The skater pushes on the wall with their hand, this action sends the ice skater moving backwards across the rink at a slow pace. If the skater applied a force on the wall, why did the wall stay still and the skater move? (a) The skater applied too much force on the wall and moved the wall back. It only appears that the skater moved backwards. B The frictional force between the skater and the ice was greater than the applied force of the wall C The skater did not applied enough force on the wall and therefore could not stand still D The wall applied an equal and opposite force to the skater causing the skater to move backward on the ice (b) Use the scenario above If the skater had a mass of…a) You wish to compare the two experimental results the physicist got, so you decide to find the percent difference between these two values using the standard equation you learned in physics class: Substitute the following values for E1 and E2 and calculate the percent difference using the formula given below: E1 9.96 m/s2 E2 9.72 m/s2 Percent differnce___DCM¹ Consider a DCM from ê to ê' that equals to the following: 0.6124 -0.2803 0.7392 0.7071 0.6124 -0.3536 0.7392 X 0.5732 Compute x, give the result with 4 decimals and verify that the properties of the DCM are satisfied.
- Force on q, by q, = 79.889N Force on q, by q, = 79.889N 91 O cm 3 4 5 7 8 10 Charge 1 Charge 2 Force Values -4 μC 2 μ Scientific Notation -10 10 -10 10 1 cmHello, can you please help me do this, make sure to do the graph, slope and intercept thanksThe curve is described by V(t)=Vm*sin(w*t+theta). Given V1=21, V3=7.518 volts, V2=-V1, and T=5.5 msec. Find Vm (volts), w (rad/sec), theta (degrees), and t4 (ms).
- S Can 6 PAR к Торс K Unit K In x K Moti = Cop K Unit S Spee S Topo S Math Micr eb.kamihq.com/web/viewer.html?source-filepicker&document_identifier=137VZR5BZOVSAIMOA55WU555_CvJ9NacO + 100 P e Interpreting Graphs Answer the questions following the graphs on each side Dietance va. Time 2 7 10 11 12 13 14 Time in soconds 1. From 1 second to 2 seconds, how fast is the object traveling. (Take the difference in distance and divide it by the time in between the 2 distances) 2. Is the object going as fast between 9 and 12 seconds as it is between 1 and 4 seconds? How can you tell? 3. What is the motion of the object between 4 and 6 seconds? acerSuppose your speedometer has an uncertainty of 4.5 km/h at a speed of 92 km/h. If the speedometer has the same percent uncertainty when it reads 55 km/h, what is the highest speed, in kilometers per hour, that you might be going? If the speedometer has the same percent uncertainty when it reads 55 km/h, what is the lowest speed, in kilometers per hour, that you might be going?length period Vlength 2. Turn your intercept into a statement. Hint: "When the is 0, the is ." cm Vcm Vx BIU EE EE O O 1. 19 0.8625 4.358898943540674 24 0.9667 4.898979485566356 29 1.1083 5.385164807134504 34 1.1958 5.830951894845301 3. Does your intercept make sense? How do you know? BIU E=E E 39 1.2292 6.244997998398398 44 1.3625 6.6332495807108 49 1.4083 7 54 1.4542 7.3484692283495345 4. A represents the slope of your line of best fit. Pay attention to the number and the unit. Mass Curve: 58 1.5375 7.615773105863909 7.937253933193772 A: 1.378 LO 63 1.6792 8.246211251235321 RMSE : 4.029 g 11 68 1.6875 Take a look at the box below your graph to find the slope of your line. What is the slope of your line? period vs Vlength BIU E= EE 1.7 1.6 1.5 1.4 5. Turn your slope into a "for every" statement. Hint: The goes up for every 1 1.3 of ." BIU E= EE 1.2 1.1 1 0.9 6. Write out the equation for your line of best fit. Hint: Make sure you have: 4.5 5 5.5 6 6.5 7 7.5 8 • Variables that…
- Enplain the equation Fz-VU.both plsImagine you derive the following expression by analyzing the physics of a particular system: v2=v20+2axv2=v02+2ax. The problem requires solving for xx, and the known values for the system are a=2.55meter/second2a=2.55meter/second2, v0=21.8meter/secondv0=21.8meter/second, and v=0meter/secondv=0meter/second. Perform the next step in the analysis.