Consider two reaction vessels, one containing A and the other containing B, with equal concentrations at t = 0. If both substances decompose by first-order kinetics, where kA = 4.10 x 10–4 s-1 kB = 4.00 x 10-3 how much time must pass to reach a condition such that [A] = 4.00(B]? Time =

Chemistry & Chemical Reactivity
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ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
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Chapter14: Chemical Kinetics: The Rates Of Chemical Reactions
Section14.4: Concentration-time Relationships: Integrated Rate Laws
Problem 3RC: 3. The equation for the decomposition of NO2(g) at 573 K is 2 NO2(g) → 2 NO(g) + O2(g). Using the...
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Consider two reaction vessels, one containing A and the other containing B, with equal concentrations at t = 0. If both substances decompose by first-order kinetics,
where
kA = 4.10 x 10
-4
-1
S
kB
- 4.00 x 10
-3
1
S
how much time must pass to reach a condition such that [A] = 4.00 B]?
Time =
S
Transcribed Image Text:Consider two reaction vessels, one containing A and the other containing B, with equal concentrations at t = 0. If both substances decompose by first-order kinetics, where kA = 4.10 x 10 -4 -1 S kB - 4.00 x 10 -3 1 S how much time must pass to reach a condition such that [A] = 4.00 B]? Time = S
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