Consider two identical antennas separated by 9.00 m that radiate in phase at 120 MHz. A receiver placed 150 m from both antennas measures an intensity I0. The receiver is moved so that it is 1.8 m closer to one antenna than to the other. a) What is the phase difference ϕ between the two radio waves produced by this path difference? b) In terms of I0, what is the intensity measured by the receiver at its new position?

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A: Wavelength , λ = 470 x 10-9 m Power , P = 210 W Distance , r = 450 m To find = Maximum rate dBdt

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A: GivenFrequency of radio waves, f=100MHz=100×106 Hz

Interference of Light

The word "constructive" signifies addition in interference. Constructive interference occurs when the path of the waves that start from the slit differs by 1 entire wavelength or in the intervals of the same. Hence, the waves that are presented on the screen are in phase (crest to crest/trough to trough). The waves interfering constructively forms bright fringes on the screen.