Consider the uniform motion of a free particle of mass m. The Hamiltonian is a constant of the motion, and so is the quantity F(x, p, t) = x − pt/m. (a) Compare {H, F} with ∂F ∂t . Prove that F is also a constant of the motion. (b) Prove that the Poisson bracket of two constants of the motion (F(x, p, t) and G(x, p, t)) is itself a constant of the motion, even if the constants F(x, p, t) and G(x, p, t) depend explicitly on the time. (c) Show in general that if the Hamiltonian and a quantity F are constants of the motion then ∂F/∂t is a constant of the motion too.
Consider the uniform motion of a free particle of mass m. The Hamiltonian is a constant of the motion, and so is the quantity F(x, p, t) = x − pt/m. (a) Compare {H, F} with ∂F ∂t . Prove that F is also a constant of the motion. (b) Prove that the Poisson bracket of two constants of the motion (F(x, p, t) and G(x, p, t)) is itself a constant of the motion, even if the constants F(x, p, t) and G(x, p, t) depend explicitly on the time. (c) Show in general that if the Hamiltonian and a quantity F are constants of the motion then ∂F/∂t is a constant of the motion too.
Related questions
Question
Consider the uniform motion of a free particle of mass m. The Hamiltonian is a constant of
the motion, and so is the quantity F(x, p, t) = x − pt/m.
(a) Compare {H, F} with ∂F
∂t . Prove that F is also a constant of the motion.
(b) Prove that the Poisson bracket of two constants of the motion (F(x, p, t) and G(x, p, t))
is itself a constant of the motion, even if the constants F(x, p, t) and G(x, p, t) depend explicitly on the time.
(c) Show in general that if the Hamiltonian and a quantity F are constants of the motion
then ∂F/∂t is a constant of the motion too.
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 7 steps with 11 images