Consider the two pairs of functions below. Between the two functions, which runs the fastest (i.e. uses the fewest number of operations), and which function runs the slowest? Does the size or order of the input change the order ranking? i.e. if the input was an array of ten million items instead of 100 or if the data was sorted (or unsorted) does the efficiency of each function change? Pair #1 def func_one(n): if (n <= 0): return 0 elif (n == 1): else: return 1 res1 = func_one(n-1) res2 = func_one(n - 2) return res1 + res2 def func_two(n): if (n <= 0): return 0 num1 = 0 num2 = 1 for i in range(1,n): temp = num1 + num2 num1 = num2 num2 = temp return num2

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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Consider the two pairs of functions below. Between the two functions, which runs the fastest (i.e. uses
the fewest number of operations), and which function runs the slowest? Does the size or order of the
input change the order ranking? i.e. if the input was an array of ten million items instead of 100 or if
the data was sorted (or unsorted) does the efficiency of each function change?
Pair #1
def func_one(n):
if (n <= 0):
elif (n
else:
return 0
1):
return 1
res1 = func_one(n-1)
res2 = func_one(n - 2)
return res1 + res2
def func_two(n):
if (n <= 0):
return 0
num1 = 0
num2 = : 1
for i in range(1,n):
temp = num1 + num2
num1 = num2
num2 = temp
return num2
Transcribed Image Text:Consider the two pairs of functions below. Between the two functions, which runs the fastest (i.e. uses the fewest number of operations), and which function runs the slowest? Does the size or order of the input change the order ranking? i.e. if the input was an array of ten million items instead of 100 or if the data was sorted (or unsorted) does the efficiency of each function change? Pair #1 def func_one(n): if (n <= 0): elif (n else: return 0 1): return 1 res1 = func_one(n-1) res2 = func_one(n - 2) return res1 + res2 def func_two(n): if (n <= 0): return 0 num1 = 0 num2 = : 1 for i in range(1,n): temp = num1 + num2 num1 = num2 num2 = temp return num2
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