Consider the pair of functions below. Between the two functions, which runs the fastest (i.e. uses the fewest number of operations), and which function runs the slowest? Does the size or order of the input change the order ranking? i.e. if the input was an array of ten million items instead of 100 or if the data was sorted (or unsorted) does the efficiency of each function change? Pair #1 def func_one(my_array): if len(my_array) > 1: mid= len(my_array)//2 L = my_array[:mid] R = my_array[mid:]

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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Consider the pair of functions below. Between the two functions, which runs the fastest (i.e. uses
the fewest number of operations), and which function runs the slowest? Does the size or order of the
input change the order ranking? i.e. if the input was an array of ten million items instead of 100 or if
the data was sorted (or unsorted) does the efficiency of each function change?
Pair #1
def func_one(my_array):
if len(my_array) > 1:
mid= len(my_array)//2
L = my_array[:mid]
R = my_array[mid:]
func_one(L)
func_one(R)
i=j= k = 0
while i < len(L) and j < len(R):
if L[i] < R[j]:
else:
k+=1
while i < len(L):
def func_two(my_array):
n = len(my_array)
for i in range(n):
i+=1
k+=
while j < len(R):
my_array[k] = L[i]
j+=1
k+=1
my_array[k] = L[i]
i+=1
my_array[k] = R[j]
j+=1
my_array[k] = R[j]
swapped = False
for j in range(0, n-i-1):
if (not swapped):
break
if my_array[i] > my_array[j+1] :
my_array[j], my_array[j+1] = my_array[j+1], my_array[j]
swapped = True
Transcribed Image Text:Consider the pair of functions below. Between the two functions, which runs the fastest (i.e. uses the fewest number of operations), and which function runs the slowest? Does the size or order of the input change the order ranking? i.e. if the input was an array of ten million items instead of 100 or if the data was sorted (or unsorted) does the efficiency of each function change? Pair #1 def func_one(my_array): if len(my_array) > 1: mid= len(my_array)//2 L = my_array[:mid] R = my_array[mid:] func_one(L) func_one(R) i=j= k = 0 while i < len(L) and j < len(R): if L[i] < R[j]: else: k+=1 while i < len(L): def func_two(my_array): n = len(my_array) for i in range(n): i+=1 k+= while j < len(R): my_array[k] = L[i] j+=1 k+=1 my_array[k] = L[i] i+=1 my_array[k] = R[j] j+=1 my_array[k] = R[j] swapped = False for j in range(0, n-i-1): if (not swapped): break if my_array[i] > my_array[j+1] : my_array[j], my_array[j+1] = my_array[j+1], my_array[j] swapped = True
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