Consider the titration of 25.00 cm³ of unknown conc NaOH with 0.090 mol dm3 HCI. If the equivalence volume for the reaction is 14.89 cm³, complete the following steps in determining the concentration of the base. i) Moles of HCI at the equivalence point = 2.25E-3 ii) Mole ratio of reaction = 1 mol NaOH : 1 mol HCI [1] mol [1] iii) Moles of NaOH neutralized at the equivalence point = 2.25E-3 iv) The concentration of NaOH in the initial 25 cm³ aliquot is = 0.151 mol [1] mol dm³ [2] Next pag

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Consider the titration of 25.00 cm³ of unknown conc NaOH with 0.090 mol dm-3 HCI. If the equivalence
volume for the reaction is 14.89 cm³, complete the following steps in determining the concentration of
the base.
i) Moles of HCI at the equivalence point = 2.25E-3
mol [1]
ii) Mole ratio of reaction = 1 mol NaOH: 1 mol HCI [1]
iii) Moles of NaOH neutralized at the equivalence point = 2.25E-3
iv) The concentration of NaOH in the initial 25 cm³ aliquot is =
MacBook Air
0.151
mol [1]
mol dm³ [2]
Next pa
Transcribed Image Text:ge Consider the titration of 25.00 cm³ of unknown conc NaOH with 0.090 mol dm-3 HCI. If the equivalence volume for the reaction is 14.89 cm³, complete the following steps in determining the concentration of the base. i) Moles of HCI at the equivalence point = 2.25E-3 mol [1] ii) Mole ratio of reaction = 1 mol NaOH: 1 mol HCI [1] iii) Moles of NaOH neutralized at the equivalence point = 2.25E-3 iv) The concentration of NaOH in the initial 25 cm³ aliquot is = MacBook Air 0.151 mol [1] mol dm³ [2] Next pa
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